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Mila [183]
4 years ago
12

Explain how variable and controlled parameters are used in scientific experiments.

Physics
2 answers:
adell [148]4 years ago
7 0

Answer:

Ok, suppose you have an experiment in which you want to see how the variable X affects the variable Y.

In this experiment, you can change the variable X and see how the other changes, and you may understand in this way how those two variables are related. Suppose that the variable X is the weight of a car and Y is the speed of the car (X is the independent variable, and Y is the dependent variable)

Now, we can change the weight and see how the speed changes in consequence. Here we also have the "controlled parameters" that are other variables that we have fixed during the experiment, in this case, we can define things like the shape of the car, the hardware, etc as controlled parameters (we even can do the same experiment again with little changes in those parameters, and in this way find the optimal combination).

aksik [14]4 years ago
5 0
Im not sure about controlled parameters, but i can explain how variables work. There are different types of variables. An independent one is the thing you change every time you do the experiment. Dependent variables are what you keep the same every time you do the experiment. (i hope this somewhat helped)
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cestrela7 [59]
Maximum generally is 20kHz
beyond 20kHz is considered ultrasound which we cant hear
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3 years ago
Why is aluminum suitable material to use in makinv cans based on its physical and chemical properties
Llana [10]

low density, malleable, easy to form into shapes, not very chem reactive

7 0
3 years ago
After three half-lives, one-ninth of an original radioactive parent isotope remains, and eight-ninths has decayed into the daugh
BartSMP [9]

Answer:

B. False

The true statement will be:

After three half-lives, one-eighth of an original radioactive parent isotope remains, and seven-eighth has decayed into daughter isotopes.

Explanation:

Half life means the time after which the amount of the given substance becomes half of its initial amount, by radiation.

Thus after each successive half life the material is halved or half of it is decayed, which leads to a general formula:

Remaining Amount = 1/2^n of parent isotope

where, n is the number of half lives passed. So, for three half-lives:

Remaining Amount = 1/2^3 of parent isotope

<u>Remaining Amount = 1/8 of parent isotope</u>

Thus, the decayed amount will be:

Decayed Amount = (1-1/8) of parent isotope

<u>Decayed Amount = 7/8 of parent isotope</u>

Thus, the given statement is <u>B.False</u>

8 0
3 years ago
The legs of a weight lifter must ultimately support the weights he has lifted. A human tibia (shinbone) has a circular cross sec
Sergio039 [100]

Answer:

249003822308.05008 N

Explanation:

F = Force

\sigma = Breaking stress of bone = 150 MPa

d_2 = Outer diameter = 3.6 cm

d_1 = Inner diameter = 2.3 cm

Area of the bone is assumed to be a hollow cylinder

A=\dfrac{\pi}{4}(d_2^2-d_1^2)

Stress is given by

\sigma=\dfrac{F}{A}\\\Rightarrow F=\sigma A\\\Rightarrow F=\dfrac{150\times 10^6}{\dfrac{\pi}{4}(0.036^2-0.023^2)}\\\Rightarrow F=249003822308.05008\ N

The maximum weight the person can lift without breaking his legs is 249003822308.05008 N

3 0
4 years ago
A car of mass 650 kg slows from a speed of 20.0 m/s to a speed of 10.0 m/s. How much kinetic energy has it lost. How much force
Natalija [7]
Formulas you need for this problem:
F= mass•acceleration
KE= mass•velocity^/2
Acceleration= final velocity-intial velocity/time
time= distance/speed

t= 97.5\10= 9.75 seconds
Acc= 10-20/9.75= -1.03 m/s/s

These are the answers :)
F=650•-1.03= -669.5N
KE= 650•100/2= 32,500J or 32.5KJ
7 0
4 years ago
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