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Lera25 [3.4K]
3 years ago
8

Please answer this correctly

Mathematics
2 answers:
Oxana [17]3 years ago
5 0

Answer:

1-20: Make it 0 units tall (change nothing)

21-40: Make it 1 unit tall

41-60: Make it 3 units tall

61-80: Make it 2 units tall

81-100: Make it 2 units tall

Step-by-step explanation:

1-20: (0 numbers)

21-40: 33 (1 number)

41-60: 43, 44, 52 (3 numbers)

61-80: 75, 79 (2 numbers)

81-100: 86, 89 (2 numbers)

Ratling [72]3 years ago
4 0
Answer: 0 in the 1-20 range, 1 in the 21-40 range, 3 in the 41-60 range, 2 in the 61-80 range, and 2 in the 81-100 range.

Explanation:

No change, 0 in the 1-20 range

33: 1 in the 21-40 range

43, 44, 52: 3 in the 41-60 range

75, 79: 2 in the 61-80 range

86, 89: 2 in the 81-100 range.
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HELPPP!!! WILL MARK BRAINLIEST!!!
LenKa [72]

Answer:

Horizontal Asymptote:    y=2

Vertical Asymptote: x=3

Step-by-step explanation:

One way: Look at graph

Look at for a horizontal or vertical line that both lines don't touch.

Second Way:

When you look for vertical asymptotes, you set the denominator equal to zero and solve.

For example, the second question has a denominator of x-3.

x-3=0

x=3 (This is the vertical asymptote)

When you look for horizontal asymptote, you do long division.

For example, the first question f(x)=\frac{2x}{x-3}

The answer will be 2. 2 is the quotient. You only want quotient not remainder.

y=2.

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2 years ago
B) If fencing costs $2.50/yd, determine the<br> costs of building the fence.
siniylev [52]
You didn’t give the rest of the answer hun
8 0
3 years ago
Northside Middle School spent $1187.50 on<br> 95 math books. How much did each book<br> cost?
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Answer:

Each book cost $12.50 dollars.

Step-by-step explanation:

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6 0
3 years ago
Read 2 more answers
To solve a system of inequalities so you can graph it how do you change these two equations into something like the two that are
Zigmanuir [339]
Explanation

Problem #2

We must find the solution to the following system of inequalities:

\begin{gathered} 3x-2y\leq4, \\ x+3y\leq6. \end{gathered}

(1) We solve for y the first inequality:

-2y\leq4-3x.

Now, we multiply both sides of the inequality by (-1), this changes the signs on both sides and inverts the inequality symbol:

\begin{gathered} 2y\ge-4+3x, \\ y\ge\frac{3}{2}x-2. \end{gathered}

The solution to this inequality is the set of all the points (x, y) over the line:

y=\frac{3}{2}x-2.

This line has:

• slope m = 3/2,

,

• y-intercept b = -2.

(2) We solve for y the second inequality:

\begin{gathered} x+3y\leq6, \\ 3y\leq6-x, \\ y\leq-\frac{1}{3}x+2. \end{gathered}

The solution to this inequality is the set of all the points (x, y) below the line:

y=-\frac{1}{3}x+2.

This line has:

• slope m = -1/3,

,

• y-intercept b = 2.

(3) Plotting the lines of points (1) and (2), and painting the region:

• over the line from point (1),

,

• and below the line from point (2),

we get the following graph:

Answer

The points that satisfy both inequalities are given by the intersection of the blue and red regions:

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