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3 years ago

Please help with A, B, and C

Mathematics

1 answer:

makkiz [27]3 years ago

4 0

A. 75 degrees because the angle creates by the car and the opposite 75 degree are vertical angles meaning that their congruent
B. 75 degrees because the 4the street and the 3rd streets are both Patel meaning that the angle of the car and the 75 degree angle on northeast angle of the fourth street are corresponding angels
C. 105 degrees because the 180 degrees which is the angle of a straight line subtracted from the 75 degree gives the answer of 105 degrees

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A student writes the difference between 15 and the product of 5 and y to describe the expression 5y negative 15

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5y means product or 5 times y
5y - 15

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3 years ago

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o-na [289]

Here I drew one to show an example
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3 years ago

G(a)=a-5 <br> h(a)=2a-4 <br> find g(h(1))

suter [353]

Calculate h(1):

h(a) = 2a - 4 → h(1) = 2(1) - 4 = 2 - 4 = -2

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<h3>Answer: g(h(1)) = -7</h3>

5 0

3 years ago

Given:

diamong [38]

Answer:

10-5 $\sqrt{2}$

Step-by-step explanation:

As per the attached figure, right angled $\triangle MDL$ has an inscribed circle whose center is $I$ .

We have joined the incenter $I$ to the vertices of the $\triangle MDL$ .

Sides MD and DL are equal because we are given that $\angle M = \angle L = 45 ^\circ.$

Formula for <em>area</em> of a $\triangle = \dfrac{1}{2} \times base \times height$

As per the figure attached, we are given that side <em>a = 10.</em>

Using pythagoras theorem, we can easily calculate that side ML = 10 $\sqrt{2}$

Points P,Q and R are at $90 ^\circ$ on the sides ML, MD and DL respectively so IQ, IR and IP are heights of $\triangle$ MIL, $\triangle$ MID and $\triangle$ DIL.

Also,

$\text {Area of } \triangle MDL = \text {Area of } \triangle MIL +\text {Area of } \triangle MID+ \text {Area of } \triangle DIL$

$\dfrac{1}{2} \times 10 \times 10 = \dfrac{1}{2} \times r \times 10 + \dfrac{1}{2} \times r \times 10 + \dfrac{1}{2} \times r \times 10\sqrt2\\\Rightarrow r = \dfrac {10}{2+\sqrt2} \\\Rightarrow r = \dfrac{5\sqrt2}{\sqrt2+1}\\\text{Multiplying and divinding by }(\sqrt2 +1)\\\Rightarrow r = 10-5\sqrt2$

So, radius of circle = $10-5\sqrt2$

8 0

3 years ago