Here are the options to the question:
A) The kinetic energy of gas particles will increase.
B) The kinetic energy of gas particles will decrease.
C) The kinetic energy of gas particles will remain unchanged.
D) The gas particles will have no kinetic energy.
<span>E) The kinetic energy of gas particles will be transferred to the container.
</span>
The best answer is:
E. The kinetic energy of gas particles will be transferred to the container
At temperatures near Zero<span> K that is −273.15 °C and −459.67 °F, nearly all molecular motion ceases and ΔS = </span>0<span> for any adiabatic process, where S is the entropy.</span>
Answer:
atoms
Explanation:
Given that,
Given mass = 13200 g
Molar mass of potassium = 39.0983 g/mol
Let there are n number of moles. It is equal to mass divided by molar mass. It is equal to :
Let there are x atoms in 13200 g of potassium (k). It can be calculated :
So, there are atoms.
The question is incomplete, the complete question is;
In a laboratory experiment, students synthesized a new compound and found that when 12.23 grams of the compound were dissolved to make 228.1 mL of a benzene solution, the osmotic pressure generated was 4.55 atm at 298 K. The compound was also found to be non-volatile and a non-electrolyte. What is the molecular weight they determined for this compound?
Answer:
287.76 g/mol
Explanation:
From;
π
=
M
R
T
M = molarity
R= gas constant
T = temperature
number of moles = π * volume/RT
number of moles = 4.55 * 228.1/1000/0.082 * 298
number of moles = 1.037855/24.436
number of moles = 0.0425 moles
Molar mass = mass/number of moles
Molar mass = 12.23 grams/0.0425 moles
Molar mass = 287.76 g/mol