It would be carbon dioxide codd2 for the molecules
Answer:
Radius of the interior sphere = 3.847 nm
Explanation:
The volume of the shell (Vs) is equal to the difference of the volume of the outer sphere (Vo) and the volume of the inner sphere (Vi). Then:

If we express the radius of the outer sphere (ro) in function of the radius of the inner sphere (ri), we have (e being the shell thickness):

The first equation becomes

To find ri that satisfies this equation we have to find the roots of the polynomial.
Numerically, it could be calculated that ri=3.847 nm satisfies the equation.
So if the radius of the interior sphere is 3.847 nm, the volume of the interior sphere is equal to the volume of the shell of 1nm.
Answer:
The answer to your question is C = 0.037 cal/g°C
Explanation:
Data
mass of the wire = m = 237 g
temperature 1 = T1 = 25°C
temperature 2 = T2 = 107°C
Heat = Q = 722 cal
Specific heat = C
Process
1.- Write the formula to find the specific heat
Q = mC(T2 - T1)
-Solve for C
C = Q / m(T2 - T1)
2.- Substitution
C = 722 / 237(107 - 25)
3.- Simplification
C = 722 / 237(82)
C = 722 / 19434
4.- Result
C = 0.037 cal/g°C
Answer:
can you show the question so we can read it