Answer:
2000pound
Explanation:
Manganese metal is produced from the manganese(III) oxide, Mn2O3, which is found in manganite, a manganese ore. The manganese is reduced from its +3 oxidation state in Mn2O3 to the zero oxidation state of the uncharged metal by reacting the Mn2O3 with a reducing agent such as aluminum or carbon. How many pounds of manganese are in 1.261 tons of Mn2O3? (1 ton = 2000 pounds)
About 40 different substances called organophosphorus compounds are registered in the United States as insecticides. They are considered less damaging to the environment than some other insecticides because they breakdown relatively rapidly in the environment. The first of these organophosphorus insecticides to be produced was tetraethyl pyrophosphate, TEPP, which is 33.11% carbon, 6.95% hydrogen, 38.59% oxygen, and 21.35% phosphorus. It has a molecular mass of 290.190.
If you’re referring to he red stuff- the liquids can be ethanol, toluene, kerosene, or isoamyl acetate. They’re transparent so they’re made more visible with red dye. (So I’d guess the answer is ethanol)
I found this in the Wikipedia article ‘Alcohol thermometer’
B. White Dwarf.
<h3>Explanation</h3>
The star would eventually run out of hydrogen fuel in the core. The core would shrink and heats up. As the temperature in the core increases, some of the helium in the core will undergo the triple-alpha process to produce elements such as Be, C, and O. The triple-alpha process will heat the outer layers of the star and blow them away from the core. This process will take a long time. Meanwhile, a planetary nebula will form.
As the outer layers of gas leave the core and cool down, they become no longer visible. The only thing left is the core of the star. Consider the Chandrasekhar Limit:
Chandrasekhar Limit: 
.
A star with core mass smaller than the Chandrasekhar Limit will not overcome electron degeneracy and end up as a white dwarf. Most of the outer layer of the star in question here will be blown away already. The core mass of this star will be only a fraction of its 
, which is much smaller than the Chandrasekhar Limit.
As the star completes the triple alpha process, its core continues to get smaller. Eventually, atoms will get so close that electrons from two nearby atoms will almost run into each other. By Pauli Exclusion Principle, that's not going to happen. Electron degeneracy will exert a strong outward force on the core. It would balance the inward gravitational pull and prevent the star from collapsing any further. The star will not go any smaller. Still, it will gain in temperature and glow on the blue end of the spectrum. It will end up as a white dwarf.
Answer:
4.50 L
Explanation:
First we <u>calculate how many moles are there in 3.84 L of a 8.50 mol/L solution</u>:
- 3.84 L * 8.50 mol/L = 32.64 mol
Now, keeping in mind that
- Concentration = Mol / Volume
we can calculate the volume of a 7.25 mol/L solution that would contain 32.64 moles:
- Volume = Mol / Concentration
- Volume = 32.64 mol ÷ 7.25 mol/L
So we could take 4.50 L of the 7.25 mol/L solution and evaporate the solvent until only 3.84 L remain.
1. An____ionic____ bond forms when one atom gives up one or more electrons to another atom.
2. Atoms or molecules with a net electric charge due to the loss or gain of one or more electrons are ions.
3. A_covalent__bond involves the sharing of electron pairs between atoms, also known as a molecular bond. 4. When one pair of electrons is shared between two atoms, a single bond is formed. 5. When two pairs of electrons are shared between two atoms, a double bond is formed. 6. A polar covalent bond is a type of chemical bond where a pair of electrons is unequally shared between two atoms. As a result, one end of the molecule has a slightly negative charge and the other a slightly positive charge. 7. Atoms involved in a nonpolar covalent bond equally share electrons; there is no charge separation to the molecule. 8. A weak bond called a van der waals bond results from an attraction between a slightly positive region in a molecule and a slightly negative region in the same or a different molecule
