The specific heat of a material is 0.137 J/g°C.
<u>Explanation:</u>
The specific heat formula relates the heat energy required to perform a certain reaction with the mass of the reactants, specific heat and the change in temperature during the reaction.
Q = mcΔT
Here m is the mass, Q is the heat energy required, ΔT is the change in temperature and c is the specific heat.
So, if we have to determine the specific heat of the object, then we have to determine the ratio of heat required to mass of the object with change in time, as shown below.
As mass of the object m is given as 35 g and the energy is said to be absorbed so Q = 96 J.
The temperature values given should be changed from kelvin to celsius first. So, initial temperature 293 K will become 293-273.15 = 19.85°C.
Similarly, the final temperature will be 313 - 273.15 = 39.85°C.
Then, ΔT = 39.85-19.85 = 20 °C
Then,
So, the specific heat of a material is 0.137 J/g°C.
I'd say that his comb has a static electricity charge. It can either be negative, or positive. Let's just say it's positive, and the water is negatively charged. This means that it will affect the water flow when the two charges meet. I hope this helps! ~Mia
1) The metal which reduces the other compound is the one higher in the reactivity. So in this case it is 
.
2) The substance which brings about reduction while itself getting oxidised (that is losing electrons) is called a reducing agent. Here, $\mathrm{Zn}$ is the reducing agent and reduces Cobalt Oxide to Cobalt while itself getting oxidised to Zinc oxide.
10. You demonstrated the difference in density of the two objects. It is a physical property.
11. First calculate the density for all of them: density = mass/volume
Density:
A. 5/6 g/ml
B. 10/9 g/ml
C. 15/16 g/ml
D. 20/10 g/ml
If the density of the substance is higher than the density of the substance it is put in, then it will sink. So substances B and D will sink in water, as their densities are higher than 1 g/ml.
12. Ammonia weighs less than water does-- for example, the weight of 8 gallons of ammonia will be equivalent to the weight of 5 gallons of water.
Hope this helped!
Answer:
1. Dmitri Mendeleev
2. Johann Dobhereiner
3. John Newlands
4. Henry Moseley
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