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LenKa [72]
3 years ago
6

Suppose you can skin a cat using either the Cox Method or the Wong Way. In the Cox Method, there are 2 steps: Step 1 can be done

in any one of 5 ways, but Step 2 can only be done one way.The Wong Way, on the other hand, requires 2 steps. Each of these steps may be completed in one of 3 ways.How many ways are there to skin a cat?
Mathematics
1 answer:
ch4aika [34]3 years ago
3 0

Answer:Looking at myy profile u know im dumb

Step-by-step explanation:

You might be interested in
Jamie's older brother and his three friends want to split the cost of lunch they also want to leave a 15% 20% tip how much shoul
Len [333]

Answer: See explanation

Step-by-step explanation:

Your question isn't well written but let me help out by making some assumptions.

Let's say Jamie's older brother and his three friends want to split the cost of lunch that costs $30 and they also want to leave a 20% tip. How much should each person pay?

Cost of the lunch = $30

Tip = 20% × $30 = 0.2 × $30 = $6

Total amount to be paid = $30 + $6 = $36

Since there are four people and they want to share the cost, each person would pay:

= $36 / 4

= $9

7 0
3 years ago
What is Y+1=2/5(x+3) in standard form
sesenic [268]

Answer:

x=  5y−1  over  2

Step-by-step explanation:

8 0
3 years ago
I talk to an average of 8 customers per hour during an 8 hour shift and need to increase the amount of customers i help by 20%,
lbvjy [14]

Answer:

The number of customer needed to achieve is 34

Step-by-step explanation:

Given as :

The number of customer per hour = 8

The time taken = 8 hours

The rate of increase = 20 %

Let The increase in number of customer after 20 % increment = x

So ,  The number of customer after n hours = initial number × (1+\dfrac{\textrm rate}{100})^{n}

or, The number of customer after 8 hours = 8 ×  (1+\dfrac{\textrm 20}{100})^{8}

or, The number of customer after 8 hours = 8 × 4.2998

∴The number of customer after 8 hours = 34.39 ≈ 34

Hence The number of customer needed to achieve is 34  answer

8 0
4 years ago
Find the LCm for the pair of natural numbers <br> 112,96
n200080 [17]

Answer:

672.

Step-by-step explanation:

First find the prime factors:

112 = 2*2*2*2*7

96 = 2*2*2*2*2*3

There are 4 pairs of duplicate 2 's  in the factors, so the LCM = 2*2*2*2*2*3*7

= 672 (answer).

Note: the duplicates only appear once in the calculation of the LCM.

5 0
3 years ago
If α and β are the zeroes of the polynomial 6y 2 − 7y + 2, find a quadratic polynomial whose zeroes are 1 α and 1 β .
ollegr [7]

Answer:

2y^2-7y+6=0

Step-by-step explanation:

We are given that \alpha and \beta are the zeroes of the polynomial 6y^2-7y+2

y^2-\frac{7}{6}y+\frac{1}{3}

We have to find a quadratic polynomial whose zeroes are 1/\alpha and 1/\beta.

General quadratic equation

x^2-(sum\;of\;zeroes)x+ product\;of\;zeroes

We get

\alpha+\beta=\frac{7}{6}

\alpha \beta=\frac{1}{3}

\frac{1}{\alpha}+\frac{1}{\beta}=\frac{\alpha+\beta}{\alpha \beta}

\frac{1}{\alpha}+\frac{1}{\beta}=\frac{7/6}{1/3}

\frac{1}{\alpha}+\frac{1}{\beta}=\frac{7}{6}\times 3=7/2

\frac{1}{\alpha}\times \frac{1}{\beta}=\frac{1}{\alpha \beta}

\frac{1}{\alpha}\times \frac{1}{\beta}=\frac{1}{1/3}=3

Substitute the values

y^2-(7/2)y+3=0

2y^2-7y+6=0

Hence, the quadratic polynomial whose zeroes are 1/\alpha and 1/\beta is given by

2y^2-7y+6=0

4 0
3 years ago
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