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raketka [301]
4 years ago
8

The Hydro water department has a monthly service charge of $13.90 and a volume charge of $1.45 for every 100 cubic feet of water

.
The total monthly cost is equal to the service charge plus the charge for the volume used during the month. If we let x represent the number of cubic feet of water (in hundreds) and y represent the total monthly cost, then we have:
total monthly cost = volume charge + service charge
y = 1.45x + 13.90

If the Johnson family used 200 ft3 more water this month than last month, then they can expect
A. an increase in their water bill of $2.90.

B. an increase in their water bill of $27.80.

C. a decrease in their water bill of $2.90.

D. a decrease in their water bill of $27.80.
Mathematics
1 answer:
erik [133]4 years ago
7 0

Answer: A

Step-by-step explanation:

In this question, you can disregard the initial $13.90 cost because we're only looking for an INCREASE in price. If the Johnson family used 200 cubic feet MORE of water, we need to multiply 2 * 1.45 which gets us 2.90. We multiply 2 by 1.45 because 200 represented in x is 2, since x is represented in hundreds.

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Bill is $75. tip is 18% what is the total bill
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Please prove this........​
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Answer:  see proof below

<u>Step-by-step explanation:</u>

Given: A + B + C = π    →     C = π - (A + B)

                                    → sin C = sin(π - (A + B))       cos C = sin(π - (A + B))

                                    → sin C = sin (A + B)              cos C = - cos(A + B)

Use the following Sum to Product Identity:

sin A + sin B = 2 cos[(A + B)/2] · sin [(A - B)/2]

cos A + cos B = 2 cos[(A + B)/2] · cos [(A - B)/2]

Use the following Double Angle Identity:

sin 2A = 2 sin A · cos A

<u>Proof LHS → RHS</u>

LHS:                        (sin 2A + sin 2B) + sin 2C

\text{Sum to Product:}\qquad 2\sin\bigg(\dfrac{2A+2B}{2}\bigg)\cdot \cos \bigg(\dfrac{2A - 2B}{2}\bigg)-\sin 2C

\text{Double Angle:}\qquad 2\sin\bigg(\dfrac{2A+2B}{2}\bigg)\cdot \cos \bigg(\dfrac{2A - 2B}{2}\bigg)-2\sin C\cdot \cos C

\text{Simplify:}\qquad \qquad 2\sin (A + B)\cdot \cos (A - B)-2\sin C\cdot \cos C

\text{Given:}\qquad \qquad \quad 2\sin C\cdot \cos (A - B)+2\sin C\cdot \cos (A+B)

\text{Factor:}\qquad \qquad \qquad 2\sin C\cdot [\cos (A-B)+\cos (A+B)]

\text{Sum to Product:}\qquad 2\sin C\cdot 2\cos A\cdot \cos B

\text{Simplify:}\qquad \qquad 4\cos A\cdot \cos B \cdot \sin C

LHS = RHS: 4 cos A · cos B · sin C = 4 cos A · cos B · sin C    \checkmark

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