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Mandarinka [93]
3 years ago
9

Please help! Plot any 6 points with x-coordinate equal to 3.

Mathematics
1 answer:
zloy xaker [14]3 years ago
7 0

Answer:

See image

Step-by-step explanation:

When all x-coordinates are the same, the equation will always be:

x = [the given x-coordinate]

In this case, the given x-coordinate is 3, meaning the equation is x = 3. x = 3 on a graph looks like the image I attached.

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OLEGan [10]
5x^2-3 is the anwser
4 0
3 years ago
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What is the equation of the line that passes through the points (−2, 1) and (1, 10)?
Viktor [21]

Answer:

3x - y = -7

Step-by-step explanation:

y = mx + b

m = deltay/deltax

m = (10 - 1)/[( 1 - (-2)]

m = 9/3 = 3

y = 3x + b

From (-2 | 1) we see that when x = -2, y = 1

Placing into the equation, in order to find b (y-intercept)

y = 3x + b

1 = 3(-2) + b

b = 7

y = 3x + 7 or 3x - y = -7

6 0
3 years ago
Please solve for the hypotenuse of a right triangle having legs 6 and 8. *
Arturiano [62]

Answer:

10

Step-by-step explanation:

6²+8²

=100

√100

=10

6 0
3 years ago
Select the statement that correctly describes the expression below
Kitty [74]

Answer:

B

Step-by-step explanation:

The equation is (2x+5)^2.

It can't be A because 2 is the multiplier for only x.

It can't be C because the square is outside of the equation.

It can't be D because again, the square is outside of the equation.

So the only thing left is B.

Hope this helped!


7 0
3 years ago
1) What is the solution of the given system?
m_a_m_a [10]

Answer:

1  x=-2.5  y = -5.5

2.  x=5  y=1

Step-by-step explanation:

1) What is the solution of the given system?

5x-y=-7

3x-y=-2

Multiply the second equation by -1

-1*(3x-y)=-1(-2)

-3x +y = 2


Now add the first equation to the modified second equation

5x-y=-7

-3x +y = 2

------------------

2x = -5

Divide each side by 2

2x/2 = -5/2

x = -2.5

Now we need to find y

-3x+y =2

-3(-2.5) +y =2

7.5 +y =2

Subtract 7.5 from each side

7.5 -7.5 +y =2-7.5

y = -5.5


2) what is the solution of the given system?

5x+7y=32

8x+6y=46

Divide the second equation by 2

8x/2+6y/2=46/2

4x+3y =23


Multiply the first equation by 4

4 (5x+7y)=32*4

20x+28y = 128


Now multiply the modified 2nd equation by -5

-5(4x+3y )=-5(23 )

-20x -15y = -115


Lets add the new equations together to eliminate x

20x+28y = 128

-20x -15y = -115

---------------------

      13y = 13

Divide each side by 13

13y/13 =13/13

y=1

Now substitute back in to find x

5x+7y=32

5x +7(1) =32

5x +7 =32

Subtract 7 from each side

5x+7-7 =32-7

5x =25

Divide by 5

5x/5 =25/5

x=5





3 0
3 years ago
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