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snow_tiger [21]
2 years ago
5

Figure A is a scale image of Figure B. What is the value of x?

Mathematics
1 answer:
Leto [7]2 years ago
5 0

Answer:

The required value of x is 12 units.

Step-by-step explanation:

Given that the figure A is a scale image of figure B.

We are to find the value of x.

Since figure A is the scale image of figure B, so both the figures are similar to each other.

Also, the corresponding sides of the similar figures are proportional, so we get

Thus, the required value of x is 12 units.

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¿El número 10.452 es divisible por 2, 3, 5, 6 y 10?
Papessa [141]
2,3,6 - yes
5,10 - no

6 0
3 years ago
True or false? The quadratic equation 10p2 - 5p = -8 has one solution.
pav-90 [236]

Answer: False

=============================================

Explanation:

I'll use x in place of p.

The original equation 10x^2-5x = -8 becomes 10x^2-5x+8 = 0 after moving everything to one side.

Compare this to ax^2+bx+c = 0

We have

  • a = 10
  • b = -5
  • c = 8

Plug those three values into the discriminant formula below

d = b^2 - 4ac

d = (-5)^2 - 4(10)(8)

d = 25 - 40*8

d = 25 - 320

d = -295

The discriminant is negative, which means we have no real solutions. If your teacher has covered complex or imaginary numbers, then you would say that the quadratic has 2 complex roots. If your teacher hasn't covered this topic yet, then you'd simply say "no real solutions".

Either way, this quadratic doesn't have exactly one solution. That only occurs when d = 0. Therefore, the original statement is false.

6 0
2 years ago
x2y - 2xy - 24y = y(x2 - 2x - 24) What is the completely factored form of x2y – 2xy – 24y? (xy + 4)(x – 6) xy(x + 4)(x – 6) y(x
likoan [24]

we are given

x^2y-2xy-24y=y(x^2-2x-24)

now, we can factor out right side term

x^2-2x-24=x^2-6x+4x-6*4

x^2-2x-24=(x-6)(x+4)

now, we can plug back

and we get

so,

x^2y-2xy-24y=y(x-6)(x+4).............Answer

5 0
3 years ago
Read 2 more answers
Rewrite: 72x3/4<br> please show how you got answer
Alex_Xolod [135]

We have been given the expression

72 \times \frac{3}{4}

We can rewrite the expression as \frac{72\times 3}{4}

In order to simplify the given expression, we can check if we have any common terms in the numerator and denominator.

We can write the term 72 which is in the numerator as 18\times 4

Thus, the expression becomes

\frac{18\times 4\times 3}{4}

We can see that 4 is common in both numerator and denominator. Hence, we can cancel 4. Thus, we are left with

18 \times 3\\&#10;=54

Therefore, we can rewrite the given expression as 54.

8 0
3 years ago
SOLVE ALL THESE EQUATION BY USING THE METHOD SUBSTITUTION ALGEBRAICALLY HERE'S ARE ALL THE EQUATION:
pav-90 [236]

Answer:

See below ~

Step-by-step explanation:

<u>Question 1</u>

  • -7x - y = -1
  • y = 8x + 16

⇒ -7x - (8x + 16) = -1

⇒ -7x - 8x - 16 = -1

⇒ -15x = 15

⇒ x = -1

⇒ y = 8(-1) + 16 = 8

⇒ Solution = <u>(-1, 8)</u>

<u></u>

<u>Question 2</u>

  • 3x + 4y = 0
  • y = -3x - 18

⇒ 3x + 4(-3x - 18) = 0

⇒ 3x - 12x - 72 = 0

⇒ -9x = 72

⇒ x = -8

⇒ y = -3(-8) - 18 = 6

⇒ Solution = <u>(-8, 6)</u>

<u>Question 3</u> (not clear)

<u>Question 4</u>

  • -8x - 7y = 0
  • y = 6x

⇒ -8x - 7(6x) = 0

⇒ -8x - 42x = 0

⇒ -50x = 0

⇒ x = 0

⇒ y = 6(0) = 0

⇒ Solution = <u>(0, 0)</u>

<u>Question 8</u>

  • 2x - 6y = -14
  • y = -5x - 19

⇒ 2x - 6(-5x - 19) = -14

⇒ 2x + 30x + 114 = -14

⇒ 32x = -128

⇒ x = -4

⇒ y = -5(-4) - 19 = 1

⇒ Solution = <u>(-4, 1)</u>

3 0
2 years ago
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