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Ber [7]
3 years ago
14

How many atoms of Mg are present in 97.22 grams of Mg?

Chemistry
1 answer:
Natasha2012 [34]3 years ago
4 0

Answer:

Second option 2.408\times10^{24}

Explanation:

Number of atoms = Number of moles x Avogadro's Number

So first we need to find the number of moles in 97.22 grams of Mg.

Atomic Mass of Mg = 24

Number of moles = n = Given Mass / Atomic Mass

n = 97.22/24 = 4.05

Now we can calculate the Number of Mg atoms in 97.22 .

Number of atoms = 4\times6.022\times10^{23}=2.408\times10^{24}

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