Question

How many atoms of Mg are present in 97.22 grams of Mg?

Answer 1

Answer:

Second option $2.408\times10^{24}$

Explanation:

Number of atoms = Number of moles x Avogadro's Number

So first we need to find the number of moles in 97.22 grams of Mg.

Atomic Mass of Mg = 24

Number of moles = n = Given Mass / Atomic Mass

n = 97.22/24 = 4.05

Now we can calculate the Number of Mg atoms in 97.22 .

Number of atoms = $4\times6.022\times10^{23}=2.408\times10^{24}$