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Llana [10]
3 years ago
13

How many liters of a 0.5 m sodium hydroxide solution would contain 2 moles of solute?

Chemistry
1 answer:
Klio2033 [76]3 years ago
7 0

Answer:

  • 4 liters

Explanation:

<u>1) Data:</u>

a) M = 0.5 M

<u>Note</u>: since the question is about volume (liters) and moles of solute, the correct unit for the concentration of the hydroxide solution is M (upper case) which is the unit for molarity. Lower case m is used for molality, and you cannot calculate the volume of the solution unless you know some other data, e.g. density of the solution.

b) n = 2

c) V (in liters) = ?

<u>2) Formula:</u>

Molarity is the number of moles of solute per liter of solution:

  • M = n / V (in liters)

<u>3) Solution:</u>

a) Clear V from the formula: V (in liters) = M / n

b) Substitute: V (in liters) =  2 moles /  0.5M  = 4 liters ← answer

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Explanation:

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Let the concentration of N2O5 after 7 min be y

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K is rate constant = 6.82×10^-3 s^-1

Initial concentration of N2O5 = number of moles/volume = 2.1×10^-2/1.8 = 0.0117 M

Change in concentration = 0.0117 - y

Time = 7 min = 7×60 = 420 s

6.82×10^-3y = 0.0117 - y/420

0.0117 - y = 420×6.82×10^-3y

0.0117 - y = 2.8644y

0.0117 = 2.8644y + y

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Answer:

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Explanation:

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First we <u>determine which reactant is limiting</u>:

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Now we calculate the moles of CO₂ produced:

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