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monitta
3 years ago
14

I need to know this what is 4.75 as a fraction can someone help

Mathematics
1 answer:
WINSTONCH [101]3 years ago
8 0

Answer:

4 \frac{3}{4}

Step-by-step explanation:

so we see a wholoe number "4", lets set that aside

we are left with 0.75 right

we can also write this as

75/100

we can simplify this by dividing 25 on both sides so it will becocme:

3/4

*Remember we have to bring the "4" we set aside earlier so final answer is*

4   and  3/4

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Solve the given inequality. Describe the solution set using the set-builder or interval notation. Then, graph the solution set o
Korolek [52]

Answer:

B

Step-by-step explanation:

10(10m+6)<=12        

100m+60<=12       Distributive Property

100m     <=12-60

100m    <=-48

     m    <=-48/100

     m    <=-.48

This says values for m that are less than or equal to -.48

-.48 is between -1 and 0 so the answer is B

6 0
4 years ago
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What is the square root of -1?
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Answer:

i

Step-by-step explanation:

<u>Step 1:  Find the square root of -1</u>

<u />\sqrt{-1}

\sqrt{i^2}

i

Answer:  i

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4 years ago
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I need answers quick. ASAP.​
LuckyWell [14K]

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(6,-6)

Step-by-step explanation:

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3 years ago
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MATH HELP!!! 100PTS!!!
Lostsunrise [7]

Answer:

x =\dfrac{20 +\sqrt{454}}{18}, \quad \dfrac{20 -\sqrt{454}}{18}

Step-by-step explanation:

<u>Given functions</u>:

  p(x)=2x-4

  r(x)=\dfrac{6x-1}{9x+1}

Solve for p(x) = r(x):

\begin{aligned}p(x) & = r(x)\\\implies 2x-4 & = \dfrac{6x-1}{9x+1}\\(2x-4)(9x+1)&=6x-1\\18x^2+2x-36x-4&=6x-1\\18x^2-40x-3&=0\end{aligned}

As the found quadratic equation cannot be factored, use the Quadratic Formula to solve for x:

<u>Quadratic Formula</u>

x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0

Therefore:

a=18, \quad b=-40, \quad c=-3

Substitute the values of a, b and c into the <u>quadratic formula</u> and solve for x:

\begin{aligned}\implies x & =\dfrac{-(-40) \pm \sqrt{(-40)^2-4(18)(-3)} }{2(18)}\\\\& =\dfrac{40 \pm \sqrt{1816}}{36}\\\\& =\dfrac{40 \pm \sqrt{4 \cdot 454}}{36}\\\\& =\dfrac{40 \pm \sqrt{4}\sqrt{454}}{36}\\\\& =\dfrac{40 \pm2\sqrt{454}}{36}\\\\& =\dfrac{20 \pm\sqrt{454}}{18}\end{aligned}

Therefore, the solutions are:

x =\dfrac{20 +\sqrt{454}}{18}, \quad \dfrac{20 -\sqrt{454}}{18}

Learn more about quadratic equations here:

brainly.com/question/27750885

brainly.com/question/27739892

6 0
2 years ago
Can somebody match these for me .
Harlamova29_29 [7]
From left to right - (-2,6) (4,1) (-2,5) top (1,-3) bottom (-4,-1) (2,-5)
8 0
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