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QveST [7]
1 year ago
15

a web server will utilize a directory protocol to enable users to authenticate with domain credentials. a certificate will be is

sued to the server to set up a secure tunnel. which protocol is ideal for this situatio
Computers and Technology
1 answer:
Allushta [10]1 year ago
7 0

The protocol is ideal for this situation is LDAP. An open, cross-platform standard called LDAP (Lightweight Directory Access Protocol) is used for directory services authentication.

An open, cross-platform standard called LDAP (Lightweight Directory Access Protocol) is used for directory services authentication. Applications can communicate with other directory services servers using LDAP, which offers a communication language.

An open, vendor-neutral application protocol for providing distributed directory information services over an IP network is called the Lightweight Directory Access Protocol (LDAP, pronounced "ldaep"). By enabling the sharing of data about users, systems, networks, services, and applications throughout the network, directory services play a crucial role in the development of intranet and Internet applications.

Using a corporate email directory as an example, directory services can offer any ordered collection of records with a hierarchical structure. A phone book is a list of subscribers with names, addresses, and phone numbers.

To know more about LDAP click here:

brainly.com/question/28364755

#SPJ4

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Assume that a gallon of paint covers about 350 square feet of wall space. Create anapplication with a main() method that prompts
Elena-2011 [213]

Answer:

import java.util.Scanner;

public class PaintClculator {

   public static void main(String[] args) {

Scanner in = new Scanner(System.in);

       System.out.println("Enter Values for length, width, and height of the room");

       double length = in.nextDouble();

       double width = in.nextDouble();

       double height = in.nextDouble();

       double wallArea = calculateWallArea(length,width,height);

       double noGallons = calculatePaint(wallArea);

       double price = price(noGallons);

       System.out.println("Price is: "+ price);

   }

   // Creating Method to Calculate Wall Area

   public static double calculateWallArea( double length, double width, double height){

       // formular for the surface area of a room Area=2*length*heigth+2*width*height+lenth*width

       double Area = 2*length*height+2*width*height+length*width;

       System.out.println("Wall Area: "+Area);

       return Area;

   }

   //Creating method to calculate amount of paint

   public static double calculatePaint(double Area){

       double noGallons = Area/350;

       System.out.println("Number of gallons: "+noGallons);

       return noGallons;

   }

   // Creating Method Calculate Price

   public static double price(double noGallons){

       return noGallons*32;

   }

}

Explanation

  1. Created Three Methods in all; calculateWallArea(), calculatePaint(), and price()
  2. Method calculateWallArea() calculates area based on this formula Area=2*length*heigth+2*width*height+lenth*width
  3. The value of Area is passed to method calculatePaint() Which calculates the number of gallons required to cover the area given that one gallon covers 350 wall space
  4. Method price() calculates and dis[plays the price by calling method calculatePaint() that returns number of gallons. since one gallon is 32$
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Which of the following is NOT a place where you are likely to encounter a pedestrian?
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Answer:

A. On a highway

Explanation:

On a highway is NOT a place where you are likely to encounter a pedestrian.

Pedestrians found on highways usually get arrested or get a ticket.

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