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3 years ago

What is the volume of 0.80 grams of O2 gas at STP?

Chemistry

2 answers:

Bingel [31]3 years ago

8 0

Answer:

0.56 liters

Explanation:

At STP, one mole of a gaseous substance occupy 22.4 liters.

Hence 1 mole of oxygen gas will occupy 22.4 liters at STP.

We know that molar mass of oxygen is 32 g/mol.

So 32 grams of oxygen gas will occupy 22.4 liters at STP.

Then 0.8 grams of oxygen gas will occupy:

$\frac{22.4}{32}\times0.8=0.56$ liters.

Hence the volume of 0.8 grams of oxygen gas at STP is 0.56 liters.

frez [133]3 years ago

5 0

Answer:

The volume of 0.80 grams of O2 is 0.56 L

Explanation:

Step 1 : Data given

Mass of O2 = 0.80 grams

Molar mass of O2 = 32 g/mol

STP = 1 mol, 1atm, 22.4 L

Step 2: Calculate moles of oxygen

Moles of O2 = Mass of O2 / molar mass of O2

Moles O2 = 0.80 grams / 32 g/mol

Moles O2 = 0.025 moles

Step 3: Calculate volume of O2

1 mol = 22.4 L of gas

0.025 moles = 0.025*22.4L = 0.56 L

The volume of 0.80 grams of O2 is 0.56 L

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Answer:

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Explanation:

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Thus, the lower the concentration of ammonia, the higher Qc, making Qc>Kc.

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Write a balanced equation for the complete oxidation reaction that occurs when ethane burns in air

damaskus [11]

<h3>Balanced equation : 2C₂H₆ (g) + 7O₂ (g) ⟶ 4CO₂ (g) + 6H₂O (ℓ)</h3><h3>Further explanation</h3>

Alkanes are saturated hydrocarbons that have single bonds in chains

General formula for alkanes :

$\tt \large{\bold{C_nH_{2n+2}}$

Hydrocarbon combustion reactions (specifically alkanes)

$\large {\box {\bold{C_nH _ (_2_n _ + _ 2_) + \dfrac {3n + 1} {2} O_2 \Rightarrow nCO_2 + (n + 1) H_2O}}}$

So that the burning of ethane with air (oxygen):

$\tt C_2H_6+\dfrac{7}{2}O_2\rightarrow 2CO_2+3H_2O$

2C₂H₆ (g) + 7O₂ (g) ⟶ 4CO₂ (g) + 6H₂O (ℓ)

or we can use mathematical equations to solve equilibrium chemical equations by giving the coefficients for each compound involved in the reaction

C₂H₆ (g) + aO₂ (g) ⟶ bCO₂ (g) + cH₂O (ℓ)

C : left 2, right b ⇒ b=2

H: left 6, right 2c⇒ 2c=6⇒ c= 3

O : left 2a, right 2b+c⇒ 2a=2b+c⇒2a=2.2+3⇒2a=7⇒a=7/2

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3 years ago

A certain electrolyte solution contains 1 gram of salt for every 8 grams of sugar and every 200 grams of water. If the sugar to

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Answer:

The resulting solution contains approximately 666 g of water.

Explanation:

In the initial solution we have:

1g salt : 8g sugar : 200g water

This means that the ratios are:

$\frac{salt}{sugar} = \frac{1}{8} \\\\\frac{sugar}{water} = \frac{8}{200} =\frac{1}{25}$

In the final solution we have:

5g salt: xg sugar: yg water

The new ratios are:

$\frac{salt}{sugar} = \frac{3}{8} \\\\\frac{sugar}{water} = \frac{1}{50}$

Now we can calculate the amount of sugar in the final solution:

$\frac{salt}{sugar} = \frac{5}{x} =\frac{3}{8} \\\\X = 13.333 g$

Finally, we calculate the amount of water:

$\frac{sugar}{water} = \frac{13.333}{y} = \frac{1}{50} \\y = 666.667 g$

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3 years ago