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alukav5142 [94]
3 years ago
15

Calculate the molarity of a solution that contains 85.0 g of Zn(C2H3O2)2 in 250. mL of solution (don't forget to convert mL to L

first). Round to the nearest hundredth.
Chemistry
1 answer:
Brilliant_brown [7]3 years ago
7 0

Answer:

[Zn(C₂H₃O₂)₂] = 1.85M (3 sig-figs accurate to 0.01 Molar)

Explanation:

Concentration is defined as amount of solute in a specified volume of solution. That is, Concentration = mass of solute/volume of solution (solution = solute + solvent). When concentration is in terms of Molar values the essential relationship is Molarity(M) = moles solute / volume of solution in liters.

For this problem => first, convert mass of Zn(C₂H₃O₂)₂ into moles and then the volume of solution into liters. Take ratio of moles/volume of solution (L).

=> Molar Concentration = moles of Zn(C₂H₃O₂)₂ / Liters of solution

moles of Zn(C₂H₃O₂)₂ = 85.0 grams Zn(C₂H₃O₂)₂ / formula weight of Zn(C₂H₃O₂)₂  =  85.0g/183.5g·mole⁻¹ = 0.463 mole Zn(C₂H₃O₂)₂.

Volume of solution in Liters = 250ml / 1000ml/L = 0.250 liters

Molarity of  Zn(C₂H₃O₂)₂ solution = 0.463 mole Zn(C₂H₃O₂)₂  /0.250 liters of solution = 1.85 Molar in Zn(C₂H₃O₂)₂

_____________

Note: The symbiology convention for 'molar solution concentration' is to place brackets around the molecular formula. That is, [Zn(C₂H₃O₂)₂] = 1.85M

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Answer:

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Explanation:

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Equation balancing can be done by "trial and error" or by algebraic method.

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Explanation: It is a stoichiometry problem and solved with the help of given grams and using balanced equation. Grams of both the reactants are converted to moles and divided by their coefficients. The excess reactant is the one for which we get the highest number on doing above steps.

The balanced equation is:

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