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natka813 [3]
2 years ago
8

a 70 g sample of cesium is sealed in a glass vial and lowered into 250 mL of water at 90 C. when the cesium melted the temperatu

re of the water dropped to 88.98 C
Chemistry
1 answer:
andre [41]2 years ago
7 0

Answer: 70.0 g  = .53 mol  

Q = 250g (+ 1.02) 4.18

Q = 1065. 9 J / 1000 = 1.0659 kJ

1.0659/ .53 = 2.01 kJ/ mol

Answer: 2.01 kJ/ mol

Explanation:

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A sample of aspirin weighing 5.945 g became contaminated with 2.134 g of sodium sulfate. The resulting
ira [324]

Answer:

The correct answer to the following question will be "62.9 %".

Explanation:

The given values are:

The aspirin's initial amount = 5.945 g.

and is polluted containing 2,134 g of sodium sulfate.

After extraction we provided 3,739 g of pure aspirin.

Now,

Percentage \ of \ recovery \ aspirin =\frac{Aspirin \ amount \ isolated \ after \ extraction}{initial \ amount \ of \ aspirin}\times 100

On putting the values in the above formula, we get

⇒                                                    =\frac{3.739}{5.945}\times 100

⇒                                                    =62.9 \ percent

Note: percent = %

7 0
3 years ago
Sodium tripolyphosphate is used in detergents to make them effective in hard water. Calculate the oxidation number of phosphorus
xz_007 [3.2K]
The answer for this question is A
4 0
3 years ago
Read 2 more answers
Sodium oxide reacts with water to make sodium hydroxide.
Vlada [557]

Answer:

So the total mass is 50 plus 150 grams the heat capacity 4.18 joules per gram per degree C. And the temperature change is 36 minus 25 and so we can calculate Delta H for the reaction that takes place.

Explanation:

3 0
2 years ago
Write the empirical formula for at least four ionic compounds that could be formed from the following ions:
CaHeK987 [17]

Answer:

Fe(CN)₂,  FeCO₃,  Pb(CN)₄,  Pb(CO₃)₂

Explanation:

Cations (positively charged ions) can only form ionic bonds with anions (negatively charged ions). However, you can't just simply put one cation and one anion together to form a compound. Each compound needs to been neutral, or have an overall charge of 0. When cations and anions do not have charges that perfectly cancel, you need to modify the amount of each ion in the compound.

1.) Fe(CN)₂
-----> Fe²⁺ and CN⁻

-----> +2 + (-1) + (-1) = 0

2.) FeCO₃

-----> Fe²⁺ and CO₃²⁻

-----> +2 + (-2) = 0

3.)  Pb(CN)₄

-----> Pb⁴⁺ and CN⁻

-----> +4 + (-1) + (-1) + (-1) + (-1) = 0

4.) Pb(CO₃)₂

-----> Pb⁴⁺ and CO₃²⁻

-----> +4 +(-2) + (-2) = 0

5 0
2 years ago
A student prepares an iron standard solution in a 50.00 mL volumetric flask. The iron stock concentration is 0.0001974 M. A stud
Serhud [2]

Answer:

0.00011765 M

Explanation:

When a solution is prepared by dilution, the volumes and concentrations are related by:

C1*V1 = C2*V2

Where C1 is the concentration of the solution 1, V1 is the volume of the solution 1, C2 is the concentration of solution 2, and V2 is the volume of solution 2.

The stock solution is the solution 1, and the standard solution, the solution 2, so:

0.0001974*29.80 = C2*50.00

C2 = 0.00011765 M

4 0
3 years ago
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