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natka813 [3]
3 years ago
8

a 70 g sample of cesium is sealed in a glass vial and lowered into 250 mL of water at 90 C. when the cesium melted the temperatu

re of the water dropped to 88.98 C
Chemistry
1 answer:
andre [41]3 years ago
7 0

Answer: 70.0 g  = .53 mol  

Q = 250g (+ 1.02) 4.18

Q = 1065. 9 J / 1000 = 1.0659 kJ

1.0659/ .53 = 2.01 kJ/ mol

Answer: 2.01 kJ/ mol

Explanation:

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Explanation:

Relation between pressure, latent heat of fusion, and change in volume is as follows.

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As, \Delta S^{fusion}_{m} = \frac{L}{T} = \frac{6010}{273.15} = 22.0 J/mol K

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where,    d_{H_{2}O} = density of water

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Therefore, using formula in equation (1) we will calculate the volume of fusion as follows.

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or,                           = 145 bar/K

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Thus, we can conclude that pressure should be increased by 681.5 bar to cause 4.7 degree change in melting point.

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