Answer:
q=mAHf
Explanation:
When water change form from solid(ice) to liquid, it will need heat that depends on the heat of fusion(Hfus). If the form changed from liquid to gas it will use the heat of vaporization(Hvap) instead. The heat of fusion usually written just AT
q=MCAT is used to calculate heat when temperature change(AT = delta T= difference in temperature)
q=mAHvap is wrong because you need if the form change from liquid to gas
q=mc^2 is wrong because it describes the relation of mass and energy, not the form.
The answer should be q=mAHf
Answer:
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Explanation:
A <em>first order reaction</em> follows the law:
, where [A] is the concentraion of the reactant A.
Equivalently:
![\dfrac{d[A]}{dt}=-k[A]](https://tex.z-dn.net/?f=%5Cdfrac%7Bd%5BA%5D%7D%7Bdt%7D%3D-k%5BA%5D)
Integrating:
![\dfrac{d[A]}{[A]}=-kdt](https://tex.z-dn.net/?f=%5Cdfrac%7Bd%5BA%5D%7D%7B%5BA%5D%7D%3D-kdt)
![\ln \dfrac{[A]}{[A_o]}=-kt](https://tex.z-dn.net/?f=%5Cln%20%5Cdfrac%7B%5BA%5D%7D%7B%5BA_o%5D%7D%3D-kt)
Half-life means [A]/[A₀] = 1/2, t = t½:
That means that the half-life is constant.
The slope of the plot of ln [N₂O₅] is -k. Then k is equal to 6.40 × 10⁻⁴ min⁻¹.
Thus, you can calculate t½:
t½ = ln(2) / 6.40 × 10⁻⁴ min⁻¹
t½ = 1,083 min.
Rounding to 3 significant figures, that is 1,080 min.
24.5 / 14 = 1.75
70 / 16 = 4.375
4.375 / 1.75 = 2.5
empirical formula = N2O5
This is an example of Oxidation
Answer:
6.33 years
Explanation:
In this question, we determine the NPER or the time period that is shown in the attached spreadsheet
Given that,
Present value = (9% × $1,000) ÷ (8.75%) = $1,028.57
Assuming figure Future value = $1,000
Rate of interest = 8.4%
PMT = $1,000 × 9% = $90
The formula is shown below:
= NPER(Rate;PMT;-PV;FV;type)
The present value come in negative
So, after solving this, the answer would be 6.33 years