Question

How many atoms of N are in 137.0 grams of N2O3?

Answer 1

1.085 x 1023 i think

hope this helps

Answer 2

Answer:

The correct answer is option D.

Explanation:

Mass of $N_2O_3$ = 137 g

Moles of$N_2O_3$

$=\frac{137.0 g}{76 g/mol}=1.8026 mole$

Number of molecules of $N_2O_3$:

$1.8026 moles\times N_A=1.8026 mol\times 6.022\times 10^{23} mol^{-1}=1.0855 \times 10^{24} molecules$

In 1 molecule of $N_2O_3$ there are two atoms of nitrogen.

Then in $1.0855 \times 10^{24} molecules$ of $N_2O_3$:

$1.0855 \times 10^{24}\times 2=2.171\times 10^{24} atoms$

The number of nitrogen atoms are $2.171\times 10^{24}$