<u>Answer:</u> The mass of required is 30.6 grams.
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
.....(1)
Given mass of chlorine gas = 25.0 g
Molar mass of chlorine gas = 71 g/mol
Putting values in equation 1, we get:
The chemical equation for the reaction of manganese (IV) oxide and hydrochloric acid follows:
By Stoichiometry of the reaction:
1 mole of chlorine gas is produced when 1 mole of is reacted.
So, 0.352 moles of chlorine gas is produced when of is reacted.
Now, calculating the mass of by using equation 1, we get:
Molar mass of = 87 g/mol
Moles of = 0.352 moles
Putting values in equation 1, we get:
Hence, the mass of required is 30.6 grams.