Question

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.

Answer 1

The solutions are $x=15, x=-8$ and $x=9$

Explanation:

Part a: The equation is $\frac{1}{3} (5x-9)=2(\frac{1}{3} x+6)$

Let us find the value of x.

Multiply the terms within the bracket, we get,

$\frac{5}{3} x-3=\frac{2}{3} x+12$

Subtracting both sides by $\frac{2}{3} x$, we have,

$\frac{3}{3} x-3=12$

Adding both sides by 3,

$x=15$

Thus, the solution of the equation $\frac{1}{3} (5x-9)=2(\frac{1}{3} x+6)$ is $x=15$

Part b: The equation is $4(3x+5)-3=9x-7$

Multiply the terms within the bracket, we get,

$12x+20-3=9x-7$

Subtracting both sides by 9x, we have,

$3x+17=-7$

Subtracting both sides by 17,

$3x=-24$

Dividing both sides by 3, we have,

$x=-8$

Thus, the solution of the equation $4(3x+5)-3=9x-7$ is $x=-8$

Part c: The equation is $5(x+7)-3(x-4)=7x+2$

Multiply the terms within the bracket, we get,

$5x+35-3x+12=7x+2$

Adding the like terms, we have,

$2x+47=7x+2$

Subtracting both sides by 2 and 2x, we get,

$45=5x$

Dividing both sides by 5, we have,

$x=9$

Thus, the solution of the equation $5(x+7)-3(x-4)=7x+2$ is $x=9$