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balandron [24]
3 years ago
5

What is the slope of the line that passes through the points (5.3) and (-4,-1)

Mathematics
1 answer:
Artemon [7]3 years ago
5 0

Answer:

y = 4/9x + 1

Step-by-step explanation:

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The temperature fell 12°F from 46°Fto 34°F in 10 hours. how much would the temperature fall over 15 hours if the pattern continu
Stolb23 [73]
18 degrees F because 
it dropped 12 degrees=10 hours
                   x degrees=15 hours
x is what you want to find out which is how many degrees it would drop in 15 hours.
12x15 then divided by 10 is 18.
5 0
3 years ago
A piece of paper is 11 inches long and 8.5 inches wide. What is the area of the paper in square centimeters? (Please show work!)
goldenfox [79]
If you would like to know what is the area of the paper in square centimeters, you can calculate this using the following steps:

1 inch equals to 2.54 centimeters.

11 inches = 11 * 2.54 = <span>27.94 centimeters long
8.5 inches = 8.5 * 2.54 = </span><span>21.59 centimeters wide

11 inches long * 8.5 inches wide = 27.94 centimeters long * 21.59 centimeters wide = </span>27.94 * 21.59 = 603.22 square centimeters
<span>
The correct result would be </span>603.22 square centimeters.<span>
</span>
3 0
3 years ago
Andre is setting up rectangle tables for a party. He can fit 6 chairs around a single table. Andre lined up 10 tables end to end
IRINA_888 [86]
If there is one table (t=1) then 6 chairs (c=6) can be placed around the table, 2 along the length on each side and 1 at each end.
When t=2, and the tables are end to end (joined at their width) c=10, that is, 4 chairs on each side of the double table and 1 at each end. Each time a table is added c increases by 4 so we can write c=4t+2 the constant 2 being the single chair at each end. If the tables are separated then c=6t.
5 0
3 years ago
Which series of transformations will not map figure H onto itself
7nadin3 [17]

Answer:

D

Step-by-step explanation:

Given a square with vertices at points (2,1), (1,2), (2,3) and (3,2).

Consider option A.

1st transformation (x+0,y-2) will map vertices of the square into points

  • (2,1)\rightarrow (2,-1);
  • (1,2)\rightarrow (1,0);
  • (2,3)\rightarrow (2,1);
  • (3,2)\rightarrow (3,0).

2nd transformation = reflection over y = 1 has the rule (x,2-y). So,

  • (2,-1)\rightarrow (2,3);
  • (1,0)\rightarrow (1,2);
  • (2,1)\rightarrow (2,1);
  • (3,0)\rightarrow (3,2)

These points are exactly the vertices of the initial square.

Consider option B.

1st transformation (x+2,y-0) will map vertices of the square into points

  • (2,1)\rightarrow (4,1);
  • (1,2)\rightarrow (3,2);
  • (2,3)\rightarrow (4,3);
  • (3,2)\rightarrow (5,2).

2nd transformation = reflection over x = 3 has the rule (6-x,y). So,

  • (4,1)\rightarrow (2,1);
  • (3,2)\rightarrow (3,2);
  • (4,3)\rightarrow (2,3);
  • (5,2)\rightarrow (1,2)

These points are exactly the vertices of the initial square.

Consider option C.

1st transformation (x+3,y+3) will map vertices of the square into points

  • (2,1)\rightarrow (5,4);
  • (1,2)\rightarrow (4,5);
  • (2,3)\rightarrow (5,6);
  • (3,2)\rightarrow (6,5).

2nd transformation = reflection over y = -x + 7 will map vertices into points

  • (5,4)\rightarrow (3,2);
  • (4,5)\rightarrow (2,3);
  • (5,6)\rightarrow (1,2);
  • (6,5)\rightarrow (2,1)

These points are exactly the vertices of the initial square.

Consider option D.

1st transformation (x-3,y-3) will map vertices of the square into points

  • (2,1)\rightarrow (-1,-2);
  • (1,2)\rightarrow (-2,-1);
  • (2,3)\rightarrow (-1,0);
  • (3,2)\rightarrow (0,-1).

2nd transformation = reflection over y = -x + 2 will map vertices into points

  • (-1,-2)\rightarrow (4,3);
  • (-2,-1)\rightarrow (3,4);
  • (-1,0)\rightarrow (2,3);
  • (0,-1)\rightarrow (3,2)

These points are not the vertices of the initial square.

5 0
3 years ago
E. Solve the Inequality
olganol [36]

        - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

\blue{\textsf{\textbf{\underline{\underline{Question:-}}}}

              Solve the Inequality.

\blue{\textsf{\textbf{\underline{\underline{Answer:-}}}}

              x<-4

\blue{\textsf{\textbf{\underline{\underline{How\:to\:Solve:-}}}}

                      First, add 6x on both sides:

-2x+3+6x<-13

Add the x's:

4x+3<-13

Now, subtract 3 on both sides:

4x<-13-3

4x<-16

Divide by 4 on both sides:

x<-4

So the values of x that are less than -4 will make the given inequality true.

<h3>Good luck.</h3>

            - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

<h3 />

7 0
2 years ago
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