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Helga [31]
3 years ago
13

Who is correct? Explain your reasoning. (Picture included)

Mathematics
1 answer:
Arada [10]3 years ago
6 0

Answer:

Gail is correct

Step-by-step explanation:

Angle 4 is congruent to <1 (vertical angles), <5 (alternate interior angles) and <8 (corresponding angles), and supplementary to the rest (e.g Angle 2 + Angle 4 = 180°)

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Find the measure of angle 1
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112*

Step-by-step explanation:

( 360 - 46 - 90 ) ÷ 2 = 112

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In the movie hidden figures what does the cop do to or For the three ladies
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the cop offers them a police escort all the way to Langley

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having a car full of african americans in a car chase a police all the way too Langley.

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Kiki works in a furniture store. Her base salary is $150 per day, plus 8 percent commission on her sales. She sells several high
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614

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On a Saturday, a library checked out 52 books. If 24 of the books were fiction, what is the ratio of non-fiction books to fictio
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6:7
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8 0
3 years ago
The thumb length of fully grown females of a certain type of frog is normally distributed with a mean of 8.59 mm and a standard
PilotLPTM [1.2K]

Answer:

21.77% probability that a randomly selected frog of this type has thumb length longer than 9.08 mm.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 8.59, \sigma = 0.63

Calculate the probability that a randomly selected frog of this type has thumb length longer than 9.08 mm.

This is 1 subtracted by the pvalue of Z when X = 9.08. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{9.08 - 8.59}{0.63}

Z = 0.78

Z = 0.78 has a pvalue of 0.7823

1 - 0.7823 = 0.2177

21.77% probability that a randomly selected frog of this type has thumb length longer than 9.08 mm.

8 0
3 years ago
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