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3 years ago

A car starts from rest and accelerates at a steady 6.00 m/s 2. How far does it travel in the first 3.00 s?

Physics

2 answers:

Ivan3 years ago

6 0

Answer:

Explanation:

Given

car starts from rest i.e. initial velocity is zero $(u=0)$

acceleration $a=6\ m\s^2$

Time take $t=3\ s$

using

$x=ut+\frac{1}{2}at^2$

where

x=displacement

u=initial velocity

a=acceleration

t=time

so car travels 27 m in first 3 second

valentina_108 [34]3 years ago

5 0

Answer:

s = 27 m

Explanation:

given,

acceleration of the car, a = 6 m/s²

time of the travel, t = 3 s

final speed of the car, v = 0 m/s

using equation of motion

v = u + a t

0 = u - 6 x 3

u = 18 m/s

initial speed of the car = 18 m/s

Again using equation of motion

v² = u² + 2 a s

0 = 18² - 2 x 6 x s

12 s = 324

s = 27 m

Distance travel by the car is equal to 27 m.

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4 years ago

If a bicyclist, with initial velocity of zero, steadily gained speed until reaching a final velocity of 39m/s, how far would she

loris [4]

Answer:

She would travel 175.5 m in the same amount of time

Explanation:

Here is the complete question:

Seven bicyclist are racing. Each bicyclist rides for 9s. If a bicyclist, with initial velocity of zero, steadily gained speed until reaching a final velocity of 39m/s, how far would she travel during the race in the same amount of time)?

Explanation:

To determine how far she would travel in the same amount of time, that is the distance she would cover in the same amount of time

From the question,

The bicyclist has an initial velocity of zero

That is, u = 0 m/s

and a final velocity of 39 m/s

That is, v = 39 m/s

Each bicyclist rides for 9s,

She also traveled for the same amount of time

that is, t = 9s

To determine the distance,

From one of the equations of motion for linear motion

s = $\frac{1}{2}$ t(u + v)

Then

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4 years ago

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Answer:

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4 years ago

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