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bearhunter [10]
3 years ago
15

A horizontal force of 200 n is applied to move a 55-kg cart (initially at rest) across a 10-m level surface. what is the final k

inetic energy of the cart?
Physics
1 answer:
Vesnalui [34]3 years ago
7 0
<span>Kinetic energy is the energy that is possessed by an object that is moving. It is calculated by one-half the product of the mass and the square of the velocity of the object. We need to determine the velocity of the cart that is moving. 
</span>
First, we use Newton's Second Law of motion;
<span>Force = ma 
200 = 55a 
a = 3.64 m/s^2 

Then, from the kinematic equation we calculate the velocity;
v^2 = v0^2 + 2ax

where v is the final velocity, v0 is the initial veocity (zero since it initially start at zero), a is the acceleration ( 3.64 m/s^2) and x is the distance traveled.

v^2 = 0^2 + 2 (3.64) (10) 
v^2 = 72.73 m^2 / s^2
v = 8.53 m / s 

KE = mv^2 / 2
KE = 1/2 (55) (8.53^2) 
KE= 2000 J</span>
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