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Ne4ueva [31]
4 years ago
15

If a bicyclist, with initial velocity of zero, steadily gained speed until reaching a final velocity of 39m/s, how far would she

travel during the race in the same amount of time)?
Physics
1 answer:
loris [4]4 years ago
5 0

Answer:

She would travel 175.5 m in the same amount of time

Explanation:

Here is the complete question:

Seven bicyclist are racing. Each bicyclist rides for 9s. If a bicyclist, with initial velocity of zero, steadily gained speed until reaching a final velocity of 39m/s, how far would she travel during the race in the same amount of time)?

Explanation:

To determine how far she would travel in the same amount of time, that is the distance she would cover in the same amount of time

From the question,

The bicyclist has an initial velocity of zero

That is, u = 0 m/s

and a final velocity of 39 m/s

That is, v = 39 m/s

Each bicyclist rides for 9s,

She also traveled for the same amount of time

that is, t = 9s

To determine the distance,

From one of the equations of motion for linear motion

s = \frac{1}{2} t(u + v)

Then

s = \frac{1}{2} (9)(0+39)

s = 4.5 (39)

s = 175.5 m

Hence, she would travel 175.5 m in the same amount of time

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A housefly walking across a clean surface can accumulate a significant positive or negative charge. In one experiment, the large
nalin [4]

Answer:

1681714.28571 N/C

Yes it could exist

Explanation:

m = Mass of housefly = 12 m

q = Charge = 70 pC

g = Acceleration due to gravity = 9.81 m/s²

E = Electric field

When an object accumulates charge it means that it is gaining electrons making it negatively charged. This is the concept of static electricity.

Here, the electric force and the graviational force will balance each other

F_e=W\\\Rightarrow qE=mg\\\Rightarrow E=\frac{mg}{q}\\\Rightarrow E=\frac{12\times 10^{-6}\times 9.81}{70\times 10^{-12}}\\\Rightarrow E=1681714.28571\ N/C

1681714.28571 N/C of electric field would be required to levitate

The direction of the electric field would be upwards vertically.

In air the critical value of electric field is 3\times 10^6\ N/C which is more than the critical value of electric field in air. So, the electric field can exist.

5 0
3 years ago
when a tuning fork vibrates over an open pipe and the air in the pipe starts to vibrate, the vibrations in the tube are caused b
malfutka [58]
Sound waves....................................
7 0
4 years ago
- A person is on an elevator that moves
Mademuasel [1]

Answer:

The net force acting on the person is, F = 560 N

Explanation:

Given data,

The downward acceleration of the elevator, a = 1.8 m/s²

The weight of the person is, W = mg

                                                          = 686 N

Therefore the mass of the person,

                                           m = W /g

                                               = 686 / 9.8

                                               = 70 kg

The net force acting on the person,

                                           F = mg - ma

                                               = 686 - 70 x 1.8

                                               = 560 N

Hence, the net force acting on the person is, F = 560 N

5 0
3 years ago
Batman (mass = 96.1 kg) jumps straight down from a bridge into a boat (mass = 458 kg) in which a criminal is fleeing. The veloci
MariettaO [177]

Answer:

The velocity of the boat after the batman lands in it is +9.26 m/s

Explanation:

Applying the law of conservation of momentum,

Total momentum before collision = Total momentum after collision.

Note: The collision between the Batman and the boat is an inelastic collision.

m'u'+mu = V(m+m').................... Equation 1

Where m' = mass of the Batman, u' = initial velcoity of the batman, m = mass of the boat, u = initial velocity of the boat, V = common velocity.

make V the subject of equation 1

V = (m'u'+mu)/(m+m')............... Equation 2

Given: m' = 96.1 kg, u' = 0 m/s, m = 458 kg, u = +11.3 m/s.

Substitute these values into equation 2

V = [(96.1×0)+(458×11.2)]/(96.1+458)

V = 5129.6/554.1

V = +9.26 m/s

8 0
3 years ago
Each student aligns the edge of the object with the left edge of the ruler and records a length of 4.6 cm. Which statement descr
TEA [102]
If they align the object at the very edge of the ruler, the measurement in inaccurate. They would have to start the measurement at 0 to get an accurate measurement. When starting at the very edge, you are not taking into account the little bit of the ruler and it between the edge of the ruler and the 0 marker.
Some people start at the 1 cm mark (and then subtract 1 from their raw measurement) to make sure they have the most accurate measurement they can get.
I'm pretty sure that is what you are talking about. Hope this helps!!
3 0
3 years ago
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