If 80 inches is equivalent to 44 inches, then 28 inches would be equivalent to what?

1. if a = 16 and b= 12, find c

klasskru [66]

Answer:

20

Step-by-step explanation:

The pythagorean theorem states that

$a^2+b^2=c^2$

So $16^2 + 12^2 = c^2\\256+144 = c^2\\400 = c^2$

You would then do

$400 = c^2\\\sqrt{400} = c$

Because a square root is the opposite of a square.

$\sqrt{400} = 20$

because 20 * 20 = 400

7 0

3 years ago

What is the measure of angle k?

Murljashka [212]

9514 1404 393

Answer:

59°

Step-by-step explanation:

Opposite angles of an inscribed quadrilateral are supplementary.

∠N +∠L = 180°

(a +16) +(a -18) = 180

2a = 182 . . . . . . . . . . add 2

a = 91 . . . . . . . . . . . . divide by 2

Then the measure of angle M is ...

∠M = (a+30)° = (91 +30)° = 121°

and angle K is its supplement.

∠K = 180° -121°

∠K = 59°

8 0

2 years ago

Use the table below to create ordered pairs.

const2013 [10]

Monday,wednesday,thursday,tuesday

7 0

3 years ago

Suppose that 14 children, who were learning to ride two-wheel bikes, were surveyed to determine how long they had to use trainin

Svetradugi [14.3K]

Answer:

CI = 3.931 < μ < 8.069

Step-by-step explanation:

Hello !

7 0

3 years ago

Jane’s buying clothes. She can get 5 shirts & 4 sweaters for $229 or she can get 2 shirts & 3 sweaters for $128. How muc

makkiz [27]

Cost of 1 shirt is $\$25$ and cost of one sweater is $\$26$

<u>Solution: </u>

Given that Jane’s buying clothes.

She can get 5 shirts & 4 sweaters for $\$229$

She can get 2 shirts & 3 sweaters for $\$128$

Need to determine cost of 1 shirt and 1 sweater.

Let assume cost of 1 shirt = $\$x$

And assume cost of 1 sweater = $\$y$

Let us create equations from give conditions

First condition is Cost of 5 shirt + cost of 4 sweater = $\$229$

$\begin{array}{l}{\text { cost of 5 shirts }=5 \times \text { cost of 1 shirt }=5 \times x=5 x} \\\\ {\text { cost of 4 sweater }=4 \times \text { cost of 1 sweater }=4 \times y=4 y}\end{array}$

So using first condition equation which we get is as follows

$5 x+4 y=229 \rightarrow (1)$

Second condition is Cost of 5 shirt + cost of 4 sweater = $\$128$

$\begin{array}{c}{\text { cost of } 2 \text { shirts }=2 \times \text { cost of } 1 \text { shirt }=2 \times x=2 x} \\\\ {\text { cost of } 3 \text { sweater }=3 \times \text { cost of } 1 \text { sweater }=3 \times y=3 y}\end{array}$

So using second condition equation which we get is as follows

$2 \mathrm{x}+3 \mathrm{y}=128\quad\rightarrow (2)$

Now we have two equations to be solved

$\begin{array}{l}{5 x+4 y=229 \rightarrow (1)} \\\\ {2 x+3 y=128 \rightarrow (2)}\end{array}$

On multiplying equation (1) by 2 and equation (2) by 5 to make coefficients of x equal in both equations, we get

$\begin{array}{l}{2 x(5 x+4 y)=2\times 229} \\\\ {10 x+8 y=458 \rightarrow (3)} \\\\ {5 x(2 x+3 y)=5 \times 128} \\\\ {10 x+15 y=640 \rightarrow (4)}\end{array}$

On subtracting (3) from (4), we get

$\begin{array}{l}{(10 \mathrm{x}-10 \mathrm{x})+(15 \mathrm{y}-8 \mathrm{y})=640-458} \\\\ {\Rightarrow 7 \mathrm{y}=182} \\\\ {\Rightarrow \mathrm{y}=\frac{182}{7}=26}\end{array}$

On substituting y = 26 in equation (1) we get

$\begin{array}{l}{\Rightarrow 5 \mathrm{x}+(4 \times 26)=229} \\\\ {\Rightarrow 5 \mathrm{x}=229-104} \\\\ {\Rightarrow 5 \mathrm{x}=125} \\\\ {\Rightarrow \mathrm{x}=\frac{125}{5}=25}\end{array}$

Cost of 1 shirt = $\$x = \$25$

Cost of 1 sweater = $\$y = \$26$

7 0

3 years ago