Expand the expression 4(x-5)
2 answers:
You might be interested in
dy/dx = 8(8x - 5)(4x² - 5x )^ 7
differentiate using the ' chain rule '
dy/dx = 8(4x² - 5x)^ 7 × d/dx (4x² - 5x)
= 8(4x² - 5x)^ 7 × (8x - 5)
= 8(8x - 5)(4x² - 5x)
dy/dx = 8(8x - 5)(4x² - 5x )^ 7
differentiate using the ' chain rule '
dy/dx = 8(4x² - 5x)^ 7 × d/dx (4x² - 5x)
= 8(4x² - 5x)^ 7 × (8x - 5)
= 8(8x - 5)(4x² - 5x)