Question

A quadratic equation is shown below:

Answer 1

the solutions to a general quadratic equation is

X=-b±√b²-4ac/2a  ,, When ax²+bx+c=0

the discriminant is the expression under the radical b²−4ac

Part A:

discriminant is (-16)² - 4(9)(60) = -1904

there are two complex solutions  

Part B:  

4x² + 8x − 5 = 0

4x² + 10x -2x - 5=0

2x ( 2x + 5) - 1(2 x + 5) =0  

(2x + 5)(2x-1) = 0

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2x+5 = 0                 2x-1 =0    

x = -5/2                     x = 1/2