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3 years ago

A quadratic equation is shown below:

Mathematics

1 answer:

AfilCa [17]3 years ago

5 0

the solutions to a general quadratic equation is

X=-b±√b²-4ac/2a ,, When ax²+bx+c=0

the discriminant is the expression under the radical b²−4ac

Part A:

discriminant is (-16)² - 4(9)(60) = -1904

there are two complex solutions

Part B:

4x² + 8x − 5 = 0

4x² + 10x -2x - 5=0

2x ( 2x + 5) - 1(2 x + 5) =0

(2x + 5)(2x-1) = 0

/ \

2x+5 = 0 2x-1 =0

x = -5/2 x = 1/2

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The table of values is shown below.

Plot these points on a coordinate plane and connect them by a free hand curve.

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The graph of function is shown below.

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