Answer:
x = 2, 4
Step-by-step explanation:
Step 1: Write out quadratic
x² - 6x + 10 = 2
Step 2: Subtract 2 on both sides
x² - 6x + 8 = 0
Step 3: Factor
(x - 4)(x - 2) = 0
Step 4: Find roots
x - 4 = 0
x = 4
x - 2 = 0
x = 2
Given one to one f(6)=3, f'(6)=5, find tangent line to y=f⁻¹(x) at (3,6)
OK, we know
f⁻¹(3)=6
The inverse function is the reflection in y=x. So slopes, i.e. the derivative will be the reciprocal. We know the derivative of f at 6 is 5, so the derivative of f⁻¹ at y=6 is 1/5, which corresponds to x=3.
f⁻¹ ' (3) = 1/5
That slope through (3,6) is the tangent line we seek:
y - 6 = (1/5) (x-3)
That's the tangent line.
y = x/5 + 27/5
Answer:
3b to the power of 3, c to the power of 4 + 2b to the power of 4, c to the power of 3b to the power of 3, c to the power of 4, + 2b tot he power of 4, c to the power of 3
Step-by-step explanation:
sorry. hope this helps I don't know how to do exponents on my computer haha
Answer:
we can use tan to solve this
tan=opposite/adjacent
tan(a)=BC/AC
tan(34)=29/AC
ACtan(34)=29
AC=29/tan(34)
by using a calculator we see that AC=42.9942678856 or 43 rounded
Step-by-step explanation:
Important variables to know:
I = interest
P = principal (investment)
R = simple interest rate
T = years
Formula: I = PRT
What information do we have?
I = $960
P = $4000
T = 3 years
R = ?
Plug into formula:
960 = 4000(3)(R)
960 = 12000R
R = 960/12000
R = .08
A. $4000 + $960 = $4960. (A= P+ I)
B. 8% (.08)
Part 2: 1080 = 4000*.09*3
A = 5080 - 4960 =$420.
