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abruzzese [7]
4 years ago
11

We can measure temperature in two different common units degrees Celsius in degrees Fahrenheit the variable X represents the tem

perature in degrees Fahrenheit that is equivalent to see the temperature in degrees Celsius F equals 32+1.8 feet what is the temperature increase in Fahrenheit is equivalent to the temperature increase of 10°C
Mathematics
1 answer:
labwork [276]4 years ago
5 0

Answer: 50° Fahrenheit

Step-by-step explanation:

Here, the equation that shows the temperature of x degree Celsius in Fahrenheit is,

F(x) = 32^{\circ} + 1.8\times x

Where x is a variable.

Thus, For the temperature of 10° Celsius,

x = 10° Celsius

The temperature in Fahrenheit is,

F(10^{\circ}C) = 32^{\circ} + 1.8\times 10

= 32^{\circ} + 18^{\circ}

=50^{\circ}\text{ Fahrenheit}

Thus, the increasing temperature by 10° C is equivalent to increasing temperature by 50° F.

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4 - x = 14<br><br><br> solve for x
VLD [36.1K]
Hey there! :)

If you switch the equation around, it becomes: 14 + x = 4

x = -10 because: -10 + 14 = 4

x = -10

Hope this helps :)
6 0
3 years ago
A bike costs $650.00. Then it is marked down 35%
Vsevolod [243]

Answer:

$422.50

Step-by-step explanation:

If the bike is marked down by 35% then the final sale price will be 65% of the original price (since 100% - 35% = 65%).

Convert 65% into a decimal:  65% = 65/100 = 0.65

Therefore, 65% of $650 = 0.65 × 650 = $422.50

6 0
3 years ago
Read 2 more answers
Sphere A and Sphere B , are similar. The volumes of A and B, are 17 and 136 cubic centimetres, respectively. The diameter of B ,
xxMikexx [17]

Answer:

3

Step-by-step explanation:

Given: Sphere A and Sphere B are similar.

The volumes of A and B are 17 cm^3and 136

The diameter of B is 6 cm.

To find: diameter of A

Solution:

Let R denotes radius of sphere A and r denotes radius of sphere B.

Radius of sphere A= R

Diameter of sphere B = 6 cm

So, radius of sphere B (r) = \frac{6}{2}=3\,\,cm

Volume of sphere is \frac{4}{3}\pi(radius)^3

Volume of sphere A = \frac{4}{3}\pi(R)^3

\frac{\frac{4}{3}\pi R^3}{\frac{4}{3}\pi r^3}=\frac{17}{136}=\frac{1}{8}\\\frac{R^3}{r^3}=\frac{1}{8}\\\frac{R}{r}=\frac{1}{2}\\r=2R

Put r = 3 cm

3=2R\\R=\frac{3}{2}=1.5\,\,cm

Diameter of sphere A = 2 × Diameter

= 2 × 1.5

=3 cm

6 0
3 years ago
I need help Please!! 1-4 Please I will Brainliest Please Help!!
Yakvenalex [24]

Answer:

1. $3

2. $14

3. 44

4. 1693

Brainliest please

4 0
3 years ago
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Bob spent 25% more time on his research project than he had planned. He had spent an extra h hours on the project. What expressi
gizmo_the_mogwai [7]

Let the projected number of work hours be w.

Then the number of hours he actually worked was 1.25w.  This represents the number of hours that Bob actually spent on the project.


Another way in which to answer this would be as follows:

Actual work hours = w + h (h hours beyond the projected w work hours).

This w + h is equivalent to 1.25w.   This means that h = 0.25w.



7 0
3 years ago
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