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abruzzese [7]
3 years ago
11

We can measure temperature in two different common units degrees Celsius in degrees Fahrenheit the variable X represents the tem

perature in degrees Fahrenheit that is equivalent to see the temperature in degrees Celsius F equals 32+1.8 feet what is the temperature increase in Fahrenheit is equivalent to the temperature increase of 10°C
Mathematics
1 answer:
labwork [276]3 years ago
5 0

Answer: 50° Fahrenheit

Step-by-step explanation:

Here, the equation that shows the temperature of x degree Celsius in Fahrenheit is,

F(x) = 32^{\circ} + 1.8\times x

Where x is a variable.

Thus, For the temperature of 10° Celsius,

x = 10° Celsius

The temperature in Fahrenheit is,

F(10^{\circ}C) = 32^{\circ} + 1.8\times 10

= 32^{\circ} + 18^{\circ}

=50^{\circ}\text{ Fahrenheit}

Thus, the increasing temperature by 10° C is equivalent to increasing temperature by 50° F.

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If you want to obtain a Class E license before you turn 18, you must______.
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3 years ago
The function f is linear. If f(2) = 2 and f(-6)=6 find f(6)
lina2011 [118]
The\ slope-intercept\ form:y=mx+b\\\\f(2)=2\to for\ x=2\to y=2\\f(-6)=6\to for x=-6\to y=6\\\\put\ in\ equation\ of\ the\ line:\\\\  -\left\{\begin{array}{ccc}2=2m+b\\6=-6m+b\end{array}\right\ \ \ |subtract\ sides\ of\ the\ equations\\----------\\.\ \ \ -4=8m\ \ \ \ \ |divide\ both\ sides\ by\ 8\\.\ \ \ \ \boxed{m=-\frac{1}{2}}\\\\put\ m=-\frac{1}{2}\ to\ equation\ 2=2m+b:\\\\2=2\cdot(-\frac{1}{2})+b\\2=-1+b\ \ \ \ |add\ 1\ to\ both\ sides\\\boxed{b=3}\\\\\boxed{\boxed{y=-\frac{1}{2}x+3}}

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5 0
2 years ago
15 pts the cost of 5 cartons of fresh ice cream is $8.75 what is the cost of 11 such cartons
Morgarella [4.7K]

Answer:

C ($19.25)

Step-by-step explanation:

First, find how much 1 carton costs, which is $8.75 divided by 5, which is $1.75. So, to find how much 11 cartons cost, we just multiply by 11 to get [tex]\boxed{\$19.25}[\tex]

5 0
2 years ago
Read 2 more answers
We did not find results for: A measure of​ malnutrition, called the​ pelidisi, varies directly as the cube root of a​ person's w
asambeis [7]
\bf \qquad \qquad \textit{double proportional variation}\\\\
\begin{array}{llll}
\textit{\underline{y} varies directly with \underline{x}}\\
\textit{and inversely with \underline{z}}
\end{array}\implies y=\cfrac{kx}{z}\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad  variation
\end{array}\\\\
-------------------------------\\\\

\bf \begin{cases}
p=pedalisi\\
w=weight\\
s=\textit{sitting height}
\end{cases}\quad 
\begin{array}{llll}
%pelidisi, varies directly as the cube root of a​ person's weight in grams and inversely as the​ person's sitting height in centimeters.
\textit{pelidisi varies directly}\\
\textit{as cube root of weight}\\
\textit{and inversely to }\\
\textit{sitting height}
\end{array}\implies p=\cfrac{k\sqrt[3]{w}}{s}\\\\
-------------------------------

\bf \textit{we know that }
\begin{cases}
w=48,820\\
s=78.7\\
p=100
\end{cases}\implies 100=\cfrac{k\sqrt[3]{48820}}{78.7}
\\\\\\
100\cdot 78.7=k\sqrt[3]{48820}\implies \cfrac{7870}{\sqrt[3]{48820}}=k
\\\\\\
thus\qquad \boxed{p=\cfrac{\frac{7870}{\sqrt[3]{48820}}\sqrt[3]{w}}{s}}
\\\\\\
\textit{now, what is \underline{p} when }
\begin{cases}
w=54,688\\
s=72.6
\end{cases}?\implies p=\cfrac{\frac{7870}{\sqrt[3]{48820}}\sqrt[3]{54688}}{72.6}

now, if that value is less than 100, then the fellow is "undernourished", otherwise, is overfed.
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