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siniylev [52]
3 years ago
6

Which type of graph would best display the monthly snowfall amounts during the winter months?

Mathematics
2 answers:
BabaBlast [244]3 years ago
7 0

That Would Be A Bar graph Because It Shows The Increase And Decrease Of Thing (Ex: Snowfall)

Anettt [7]3 years ago
4 0
Bar graph <span> would best display the monthly snowfall amounts during the winter months
</span>a graph using parallel bars of varying lengths, as to illustratecomparative costs, exports, birth-rates, <span>etc.
</span>option A is right 
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Talia has a daily budget of $94 for a car rental. Write and solve an inequality to find the greatest distance Talia can drive ea
MariettaO [177]

Answer:

Step-by-step explanation:

Distance traveled by Talia = x

Cost for travelling 'x' miles = x * 0.20 = 0.2x

Daily budget = $94

Inequality,

30 + 0.2x ≤ 94

Solution:

0.2x ≤ 94 - 30      

0.2x ≤ 64        {Divide both sides by 0.2

   x ≤ 64/0.2

 x ≤ 320

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3 years ago
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-1(t+8)=-7.1 solve for t
Darina [25.2K]

Answer:

t = -0.9

Step-by-step explanation:

-1(t+8) = -7.1

(t+8) = 7.1

t = -0.9

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3 years ago
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A professor pays 25 cents for each blackboard error made in lecture to the student who pointsout the error. In a career ofnyears
marta [7]

Answer:

(a) The probability that <em>Y</em>₂₀ exceeds 1000  is 3.91 × 10⁻⁶.

(b) <em>n</em> = 28.09

Step-by-step explanation:

The random variable <em>Y</em>ₙ is defined as the total numbers of dollars paid in <em>n</em> years.

It is provided that <em>Y</em>ₙ can be approximated by a Gaussian distribution, also known as Normal distribution.

The mean and standard deviation of <em>Y</em>ₙ are:

\mu_{Y_{n}}=40n\\\sigma_{Y_{n}}=\sqrt{100n}

(a)

For <em>n</em> = 20 the mean and standard deviation of <em>Y</em>₂₀ are:

\mu_{Y_{n}}=40n=40\times20=800\\\sigma_{Y_{n}}=\sqrt{100n}=\sqrt{100\times20}=44.72\\

Compute the probability that <em>Y</em>₂₀ exceeds 1000 as follows:

P(Y_{n}>1000)=P(\frac{Y_{n}-\mu_{Y_{n}}}{\sigma_{Y_{n}}}>\frac{1000-800}{44.72})\\=P(Z>  4.47)\\=1-P(Z

**Use a <em>z </em>table for probability.

Thus, the probability that <em>Y</em>₂₀ exceeds 1000  is 3.91 × 10⁻⁶.

(b)

It is provided that P (<em>Y</em>ₙ > 1000) > 0.99.

P(Y_{n}>1000)=0.99\\1-P(Y_{n}

The value of <em>z</em> for which P (Z < z) = 0.01 is 2.33.

Compute the value of <em>n</em> as follows:

z=\frac{Y_{n}-\mu_{Y_{n}}}{\sigma_{Y_{n}}}\\2.33=\frac{1000-40n}{\sqrt{100n}}\\2.33=\frac{100}{\sqrt{n}}-4\sqrt{n}  \\2.33=\frac{100-4n}{\sqrt{n}} \\5.4289=\frac{(100-4n)^{2}}{n}\\5.4289=\frac{10000+16n^{2}-800n}{n}\\5.4289n=10000+16n^{2}-800n\\16n^{2}-805.4289n+10000=0

The last equation is a quadratic equation.

The roots of a quadratic equation are:

n=\frac{-b\pm\sqrt{b^{2}-4ac}}{2a}

a = 16

b = -805.4289

c = 10000

On solving the last equation the value of <em>n</em> = 28.09.

8 0
3 years ago
A single tree produces about 2.6 × 102 lb of oxygen each year. The Amazon rainforest has about 3.9 × 1011 trees.
ankoles [38]

(2.6 x 10² lb/tree) x (3.9 x 10¹¹ tree) = 1.014 x 10¹⁴ pounds .

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3 years ago
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Provide an Example of how to draw transformed figures that are translated, reflected, and rotated.
solniwko [45]

Step-by-step explanation:

Translations: When a figure is slid to another place on the coordinate grid (for example if i asked you to move the figure 2 units down and 4 units to the left)

Reflected: When a figure is reflected across the y-axis or the x-axis and both figures are congruent to each other.

Rotated: When a figure is rotated (for example if i asked you to rotate the figure 90 degrees)

7 0
3 years ago
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