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Licemer1 [7]
4 years ago
6

What is the median 7,11,10,13,17,23,25,25,20,18,12,9

Mathematics
2 answers:
frosja888 [35]4 years ago
6 0
The answer will be 15.
ratelena [41]4 years ago
3 0
The median is 24 because u have two 23 and 25 u add it  then divide by 2
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What is the measure of the secant AB
cricket20 [7]
A secant is a line that intersects a circle in exactly two points. When a tangent and a secant, two secants, or two tangents intersect outside a circle than the measure of the angle is formed is one-half the positive difference of the measures of the intercepted arcs.
6 0
3 years ago
There are 4 different math courses, 5 different science courses, and 2 different history courses. If a student must take one of
rusak2 [61]

A student can take three subjects in 40 ways.

<u>SOLUTION:</u>

Given that, there are 4 different math courses, 5 different science courses, and 2 different history courses.

A student must take one of each, how many different ways can this be done?

Now, number ways to take math course = 4

Number of ways to take science course = 5  

Number of ways to take history course = 2

So, now, total possible ways = product of possible ways for each course = 4 x 5 x 2 = 40 ways.

Hence, a student can take three subjects in 40 ways.

6 0
3 years ago
Solve the inequaliy: (x^2+2)(x−2)^2(6−2x)&gt;0
marin [14]
The answer is x<2
-2x^5 + 14x^4 - 36x^3 + 52x^2 - 64x + 48=0
7 0
4 years ago
The length of a rectangle is 5 more than twice the width. the perimeter is 130. what is the area?
vekshin1
<span>L the length     W the width 

The length of a rectangle is 5 more than twice the width</span>
L = 5+ 2W

<span>the perimeter is equal the sum of sides =130
</span>
L+L+W+W =130

by subtitution we replace L by <span>L = 5+ 2W

</span>5+ 2W+<span>5+ 2W +W+W = 130
</span>
6W= 120

w= 20              <span>L = 5+ 2W= 5+ 40=45</span>
7 0
3 years ago
Les municipalités de Sainte-Julie,
Ludmilka [50]

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CNC app BC we can we can MN we all at can we can we do all we can we go we go we cannot GL can see VM we BM

6 0
3 years ago
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