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Mariulka [41]
3 years ago
10

Simplify the expression. : 5 + 4 x (8 - 6) square

Mathematics
2 answers:
UNO [17]3 years ago
8 0

Answer:

8x+5

Step-by-step explanation:

8-6=2

2× 4x= 8x

8x+5

tensa zangetsu [6.8K]3 years ago
6 0

Answer:

<h3>\boxed{ \huge{ \bold{ \sf{  \boxed{21}}}}}</h3>

Step-by-step explanation:

Use PEMDAS rule :

P = Parentheses

E = Exponents

M = Multiplication

D = Division

A = Addition

S = Subtraction

Let's solve :

\sf{5 + 4  \times  {(8 - 6)}^{2} }

⇒\sf{5 + 4 \times  {2}^{2} }

⇒\sf{5 + 4 \times 4}

⇒\sf{5 + 16}

⇒\sf{21}

Hope I helped!

Best regards!

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Answer:

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Step-by-step explanation:

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the Following table shows alexandra's investment options over the course of three years. Her initial investment was $1,000 . wri
Y_Kistochka [10]

The pattern in the given series of amount in the account are in the form of

arithmetic and geometric progression.

  • The function for Option 1 is;  \underline{ f(n) = 1,100 + (n - 1) \cdot 100}
  • The function for Option 2 is; \underline{f(n) = 1,100 \times  1.1^{(n - 1)}}

Reasons:

The given table of values is presented as follows;

\begin{tabular}{c|c|c|c|}Number of years&1&2&3\\Option 1 (Amount in dollars)&1,100&1,200&1,300\\Option 2 (Amount in dollars)&1,100&1,210&1,331\end{array}\right]

In Option 1, the amount in dollars for each year has a common difference of d = 100

The first term, a = 1,100

Therefore;

The Option 1 can be represented as an arithmetic progression , A.P. in the

form, tₙ = a + (n - 1)·d as follows;

For the Option 1, we have;

  • The amount in dollars after <em>n</em> years, \underline{ f(n) = 1,100 + (n - 1) \cdot 100}

For Option 2, it is possible to find;

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Therefore;

The terms in the Option 2 have a common ratio of r = 1.1

The Option 2 is a geometric progression, G.P.

The first term in Option 2 is a = 1,100

Which gives, the nth term, tₙ = a·r⁽ⁿ ⁻ ¹⁾

Therefor;

  • The function for the Option 2 is; \underline{f(n) = 1,100 \times  1.1^{(n - 1)}}

Learn more about arithmetic and geometric progression here:

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4 0
2 years ago
What does the quadratic function f(x)=x^2-10x+9 look like when it is rewritten in the form f(x) = a (x-h) + k
Tatiana [17]

ANSWER

When f(x)=x^2-10x+9 is written in the form f(x)=a(x-h)^2+k, it looks like f(x)=(x-5)^2-16


EXPLANATION

To write  f(x)=x^2-10x+9 in the form f(x)=a(x-h)^2+k, we have to complete the squares.


We add and subtract half the coefficient of x square.


f(x)=x^2-10x+(-5)^2-(-5)^2+9


The first three terms of the function is now a perfect square.

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