Answer:
disagree
Explanation:
Cellulose (main component of wood beside lignin) is composed from carbon, hydrogen and oxygen with the following molecular formula (C₆H₁₀O₅)ₓ (where x is the degree of condensation of beta-glucose units which are the basic monosaccharide of the cellulose polysaccharide).
Now when you burn cellulose you obtain carbon (ashes), carbon dioxide (CO₂) and water (H₂O). Of course, beside the main products we may have other by-products but we consider them in very low quantity.
The difference between 3 kg of starting wood and 500 g of ashes is representing the quantity of carbon dioxide (CO₂) and water (H₂O) formed.
We have to say that CO₂ and H₂O are in gaseous state and escape in the atmosphere.
The law of conservation of mass is always valid.
Answer:
0.052 M.
Explanation:
Hello!
In this case, since the molarity is computed by dividing the moles of the solute by the volume of the solution in liters (M=n/V), we first need to compute the moles in 5.025 grams of NaOH as shown below:
![n=5.025g*\frac{1mol}{40.0g}\\\\n=0.126mol](https://tex.z-dn.net/?f=n%3D5.025g%2A%5Cfrac%7B1mol%7D%7B40.0g%7D%5C%5C%5C%5Cn%3D0.126mol)
In such a way, we compute the molarity as show below:
![M=\frac{0.126mol}{2.4L}\\\\M=0.052M](https://tex.z-dn.net/?f=M%3D%5Cfrac%7B0.126mol%7D%7B2.4L%7D%5C%5C%5C%5CM%3D0.052M)
Best regards!
Answer:
Be the anode
Explanation:
The standard hydrogen electrode is regarded as the standard reference electrode and it has been assigned an electrode potential of 0.0V.
If any substance has an electrode potential that is more negative than hydrogen, then that half cell will function as the anode when connected to the standard hydrogen electrode.
Similarly, any substance that has a more positive electrode potential than hydrogen will serve as the cathode when its half cell is connected to the standard hydrogen electrode.
Answer:
When a gas is heated, the molecules move faster, bump into each other, and spread apart. Because the molecules are spread apart, they take up more space. They are less dense.