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harkovskaia [24]
3 years ago
10

Rahul burnt 3kg of fire wood got only 500 g of ashes and says that Law of conservation of mass is not valid do you agree or disa

gree
Chemistry
1 answer:
N76 [4]3 years ago
3 0

Answer:

disagree

Explanation:

Cellulose (main component of wood beside lignin) is composed from carbon, hydrogen and oxygen with the following molecular formula  (C₆H₁₀O₅)ₓ (where x is the degree of condensation of beta-glucose units which are the basic monosaccharide of the cellulose polysaccharide).

Now when you burn cellulose you obtain carbon (ashes), carbon dioxide (CO₂) and water  (H₂O). Of course, beside the main products we may have other by-products but we consider them in very low quantity.

The difference between 3 kg of starting wood and 500 g of ashes is representing the quantity of carbon dioxide (CO₂)  and water (H₂O) formed.

We have to say that CO₂ and H₂O are in gaseous state and escape in the atmosphere.

The law of conservation of mass is always valid.

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kompoz [17]

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8 0
3 years ago
What mass of solid that has a molar mass of 46.0 g/mol should be added to 150.0 g of benzene to raise the boiling point of benze
enyata [817]

Answer : 17.12 g

Explanation:\Delta T =k_b\times m

\Delta T = elevation in boiling point

k_b = boiling point elevation constant

m= molality

molality=\frac{mass of solute}{molecular mass of solute\times weight of the solvent in kg}

given \Delta T=6.28^{\circ}C

Molar mass of solute = 46.0 gmol^{-1}

Weight of the solvent = 150.0 g = 0.15 kg

Putting in the values

molality=\frac{x}{46gmol^{-1}\times0.15kg}

6.28 =2.53^{\circ}Ckgmol^{-1}\frac{x}{46gmol^{-1}\times 0.15kg}

x = 17.12 g



3 0
3 years ago
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Explanation:

8 0
3 years ago
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The mass of an atomic number best refers to the number of
adelina 88 [10]

Answer:

Mass number

Explanation:

5 0
3 years ago
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If the mass of the object below is 28g, what is the density of the object below. Units are in cm below. Please round your answer
Murljashka [212]

Answer:

d = 0.93 g/cm³

Explanation:

Given data:

Mass of object = 28 g

Volume of object = 3cm×2cm×5cm

density of object = ?

Solution:

Volume of object = 3cm × 2cm ×5cm

Volume of object = 30 cm³

Density of object:

d = m/v

by putting values,

d = 28 g/ 30 cm³

d = 0.93 g/cm³

3 0
3 years ago
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