A cloud that forms on the ground is called fog. Some clouds you see in the sky might be from airplanes. These are called contrails. High level cirrus clouds may travel at speeds up to 100 mph.
Answer:
1. -4
2. +1
3. 0
4. +4
5. -2
6. +1
7. -2
reduced = H
oxidized = O
Explanation:
Know oxidation rules.
- Hope this helped! Please let me know if you would like to learn this. I could show you the rules and help you work through them.
The formula for average atomic mass is :
mass of isotope A * % of isotope A + mass of isotope B * % of isotope B + ....
Now,
Here,
Average atomic mass of nitrogen = (14.003 * 99.63%) + (15.000 * 0.37%)
= (14.003 * 0.9963) + ( 15.000 * 0.0037)
= 13.951 + 0.056
= 14.007 a.m.u.
Answer:
78
Explanation:
That's my score when I did a 3-minute Step test
Answer:
concentration of
= 0.0124 = 12.4 ×10⁻³ M
concentration of
= 0.0248 = 2.48 ×10⁻² M
concentration of
= 0.4442 M
Explanation:
Equation for the reaction:
⇄
+ 
Concentration of
=
= 0.469
For our ICE Table; we have:
⇄
+ 
Initial 0.469 0 0
Change - 2x +2x +x
Equilibrium (0.469-2x) 2x x
K = ![\frac{[CO]^2[O]}{[CO_2]^2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BCO%5D%5E2%5BO%5D%7D%7B%5BCO_2%5D%5E2%7D)
K = ![\frac{[2x]^2[x]}{[0.469-2x]^2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5B2x%5D%5E2%5Bx%5D%7D%7B%5B0.469-2x%5D%5E2%7D)

Since the value pf K is very small, only little small of reactant goes into product; so (0.469-2x)² = (0.469)²




![x=\sqrt[3]{1.9929*10^{-6}}](https://tex.z-dn.net/?f=x%3D%5Csqrt%5B3%5D%7B1.9929%2A10%5E%7B-6%7D%7D)
x = 0.0124
∴ at equilibrium; concentration of
= 0.0124 = 12.4 ×10⁻³ M
concentration of
= 2x = 2 ( 0.0124)
= 0.0248
= 2.48 ×10⁻² M
concentration of
= 0.469-2x
= 0.469-2(0.0124)
= 0.469 - 0.0248
= 0.4442 M