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Svet_ta [14]
4 years ago
13

If E°(red) of a given half-cell is more negative than E°(red) for a standard hydrogen electrode, the half-cell will:

Chemistry
1 answer:
Scorpion4ik [409]4 years ago
7 0

Answer:

Be the anode

Explanation:

The standard hydrogen electrode is regarded as the standard reference electrode and it has been assigned an electrode potential of 0.0V.

If any substance has an electrode potential that is more negative than hydrogen, then that half cell will function as the anode when connected to the standard hydrogen electrode.

Similarly, any substance that has a more positive electrode potential than hydrogen will serve as the cathode when its half cell is connected to the standard hydrogen electrode.

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It is A. mitochondrion 
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PLZ HELP I WILL REWARD BRAINLIEST IF U ANSWER CORRECTLY WITH A REASON WHY :)
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Answer:

The answer is dipole-dipole forces.

Explanation:

The molecule is composed of Sulfur and Oxygen, which are both elements with high electronegativities. As a result, this is a covalent bond, as they are both nonmetals. Since Sulfur has a partially positive charge, and Oxygen has a partially negative charge, it appears that the substance is polar, meaning that there are different charges within the atom. Of the answer choices, Dipole-Dipole forces are the only ones that involve polar substances, and they different charges, especially since there is no hydrogen indicating a hydrogen bond, and London forces contain nonpolar substances with an overall charge of the molecule.

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3 years ago
In a vacuum, with no air resistance, how do 2 objects of different weights compare when falling?
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Answer

hope it helps

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4 years ago
The amount of heat involved in the synthesis of 1 mole of a compound from its elements, with all substances in their standard st
Pachacha [2.7K]

Answer:

A

Explanation:

8 0
4 years ago
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17) Chlorine and Fluorine react to form gaseous chlorine trifluoride. You start with 1.75 mole of chlorine and 3.68 moles of flu
Mama L [17]

Answer:

a) Cl_2 + 3F_2 \rightarrow 2ClF_3

b) F_2 is the limiting reagent

c) Moles of ClF_3 produced = 2.45 mol

b) Moles of Cl_2 left = 1.75 -1.22 = 0.53

Explanation:

a) Balanced reaction:

Cl_2 + 3F_2 \rightarrow 2ClF_3

b)

No. of mole of Cl_2 = 1.75\ mol

No. of mole of F_2 = 3.68\ mol

Cl_2 + 3F_2 \rightarrow 2ClF_3

As, it is clear from the reaction that,

1 mol of Cl_2 requires 3 moles of F_2

1.75 mol of Cl_2 require = 1.75 × 3 = 5.25 mol of F_2

As, only 3.68 mol of F_2 is present, so F_2 is the limiting reagent.

c)

3 moles of F_2 form 2 moles of ClF_3

3.68 moles of F_2 will form = \frac{2}{3}  \times 3.68 = 2.45\ mol\ of\ ClF_3

d)

Cl_2 is present in excess.

3 moles of F_2 requires 1 mol of Cl_2

3.68 moles of F_2 will require = \frac{1}{3} \times 3.68 = 1.22\ mol\ of\ Cl_2

Cl_2 left = 1.75 -1.22 = 0.53 mol

6 0
4 years ago
Read 2 more answers
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