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professor190 [17]
3 years ago
11

amy purchases 27 teeshirts for a certain amount of money. using m for the total amount of money in dollars that amy spent on tee

shirts, write an expression that represents how much one teeshirt costs.
Mathematics
1 answer:
Sophie [7]3 years ago
4 0
<span>One T-shirt is m dollars. The number of T-shirts is n. Amy bought 27 T-shirts. 

27n = m, so n = m/27.</span><span>
Hope that helps! (:</span>
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How many points are collinear with points Cand D?
asambeis [7]

Answer: B) one

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3 years ago
What is the equation of this graphed line?
Eva8 [605]

Answer:

  • y = -9/8x + 7

Step-by-step explanation:

<u>Slope-intercept form is:</u>

  • y = mx + b

<u>Points given:</u>

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<u>y-intercept is </u>

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6 0
3 years ago
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Point Q is the center of dilation. Lines segment S U is dilated to form line segment S prime U prime. The length of Q S is 3 .2
tia_tia [17]

Answer:

Option C.

Step-by-step explanation:

It is given that the dilation rule is D_{Q,2.5}. It means the center of dilatation is point Q and scale factor is 2.5.

Scale factor is the ratio of distance from center to the image of a point and distance from center to the corresponding point.

\text{Scale factor}=\dfrac{QU'}{QU}

It is given that QU=4 and scale factor = 2.5.

2.5=\dfrac{QU'}{4}

Multiply both sides by 4.

2.5\times 4=QU'

10=QU'

We know that

UU'=QU'-QU

UU'=10-4

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The distance between U' and U is 6 units.

Therefore, the correct option is C.

8 0
3 years ago
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What is 2 5/6 + 7/4 <br> A. 2 2/5<br> B. 3 1/5<br> C. 3 4/5<br> D. 4 7/12
Mazyrski [523]

Answer:

D

Step-by-step explanation:

2 5/6=2 10/12

7/4=1 3/4= 1 9/12

2 10/12+1 9/12= 4 7/12

you can just change the denominators to the same which is 12. Hope you appreciate it!

7 0
3 years ago
The graph of f ′ (x), the derivative of f(x), is continuous for all x and consists of five line segments as shown below. Given f
Nataliya [291]

The maxima of f(x) occur at its critical points, where f '(x) is zero or undefined. We're given f '(x) is continuous, so we only care about the first case. Looking at the plot, we see that f '(x) = 0 when x = -4, x = 0, and x = 5.

Notice that f '(x) ≥ 0 for all x in the interval [0, 5]. This means f(x) is strictly increasing, and so the absolute maximum of f(x) over [0, 5] occurs at x = 5.

By the fundamental theorem of calculus,

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The definite integral corresponds to the area of a trapezoid with height 2 and "bases" of length 5 and 2, so

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8 0
3 years ago
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