Answer:
0.04578
Step-by-step explanation:
Hope this helps somewhat.
In order to solve this problem, you must draw a right triangle first to help you visualize the path of the jogger.
You are given 0.5 miles north (which will be the height of the right triangle), and 1.3 miles (which will be the hypotenuse of the triangle).
Using Pythagorean Theorem: a²+b²=c², we have:
0.5² + b² = 1.3²
b = 1.3²-0.5²
b = 1.2 miles
Given :
Ryan works two jobs. He earns $10 per hour working at the hardware store, and he earns $13 per hour working at the shipping.
To Find :
If x represents hours at the hardware store and y represents hours at the shipping company, which inequality represents the situation if Ryan wants to earn a minimum of $300.
Solution :
His total earning is given by :
T = 10( number of hours at hardware store ) + 13( number of hours at the shipping)
T = 10x + 13y
Now, he wants to earn a minimum of $300 i.e T ≥ $300.
So, 10x + 13y ≥ 300
Hence, this is the required solution.
Answer:
Step-by-step explanation:
When a slope of a line and a point passing through it is given then we use slope - one point form to determine the equation of the line.
It is given by:
where 
is the slope of the line and
is the point passing through it.
Here, 
and 
Substituting in the equation:
Answer:
The 95% Confidence Interval for the difference between the two population mean completion times =
(0.081, 1.919)
Step-by-step explanation:
Confidence Interval for difference between two means =
μ1 -μ2 ± z × √ σ²1/n1 + σ²2/n2
Where
μ1 = mean 1 = 12 mins
σ1 = Standard deviation 1 = 2 mins
n1 = 100
μ2= mean 2 = 11 mins
σ2 = Standard deviation 2 = 3 mins
n1 = 50
z score for 95% confidence interval = 1.96
μ1 -μ2 ± z × √ σ²1/n1 + σ²2/n2
= 12 - 11 ± 1.96 × √2²/100 + 3²/50
= 1 ± 1.96 × √4/100 + 9/50
= 1 ± 1.96 × √0.04 + 0.18
= 1 ± 1.96 × √0.22
= 1 ± 1.96 × 0.469041576
= 1 ± 0.9193214889
Confidence Interval
= 1 - 0.9193214889
= 0.0806785111
≈ 0.081
1 + 0.9193214889
= 1.9193214889
≈ 1.919
Therefore, the 95% Confidence Interval for the difference between the two population mean completion times =
(0.081, 1.919)
