A case of 24 cans contains 1 can that is contaminated. Three cans are chosen randomly for testing. How many different combinatio
ns of 3 cans could be selected?
1 answer:
C(24,3) which means the number of combinations of 24 cans taken 3 at a time.
C( 24, 3) = 2024
24! divided by the product of (3! * 21!)
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