Question

A case of 24 cans contains 1 can that is contaminated. Three cans are chosen randomly for testing. How many different combinations of 3 cans could be selected?

Answer 1

C(24,3) which means the number of combinations of 24 cans taken 3 at a time.

C( 24, 3) = 2024

24! divided by the product of (3! * 21!)