The first step for solving this equation is to determine the defined range.

, x ≠ 1
Remember that when the denominators of both fractions are the same,, you need to set the numerators equal. This will look like the following:

= 5
Take the root of both sides of the equation and remember to use both positive and negative roots.
x +/-
![\sqrt[4]{5}](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B5%7D)
Separate the solutions.
x =
![\sqrt[4]{5}](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B5%7D)
, x ≠ 1
x = -
Check if the solution is in the defined range.
x =
x = -
This means that the final solution to your question are the following:
x =
x = -
Let me know if you have any further questions.
:)
Answer:
see explanation
Step-by-step explanation:
Calculate the distance (d) using the distance formula
d = √ (x₂ - x₁ )² + (y₂ - y₁ )²
with (x₁, y₁ ) = (6, 5) and (x₂, y₂ ) = (- 3, 1)
d = 
= 
= 
=
≈ 9.85 ( to 2 dec. places )
If you’re simplifying it’s 100x^2+200x+5
Answer:
13.60 See the note below.
Step-by-step explanation:
Remark
This is just the reverse of the question you just did. This time you are trying to solve for c
Givens
Solution
c^2 = a^2 + b^2 Substitute the givens.
c^2 = 8^2 + 11^2 Expand
c^2 = 64 + 121 Combine the right side by adding
c^2 = 185 Take the square root of both sides.
sqrt(c^2) = sqrt(185) Complete the operation
c = 13.601 Round to the nearest 1/100 th
c = 13.60 Note: the zero must be there or the answer does not show the nearest 1/100 th