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Studentka2010 [4]
2 years ago
15

Which Values of P and Q result in an equation with exactly one solution?

Mathematics
2 answers:
galben [10]2 years ago
8 0
I don’t get this at all sorry I’m no help
abruzzese [7]2 years ago
4 0

Answer:

the answer is c

Step-by-step explanation:


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Can someone please help me?
Feliz [49]

Answer:

m<2 = 150

Step-by-step explanation:

m<2 = 150 because of alternate exterior angles

7 0
2 years ago
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tamaranim1 [39]

Answer:

  • The function is injective but nor surjective

Step-by-step explanation:

<u>We see that:</u>

  • f(x) = x³

<u>For any x₁ and x₂ ∈ N, </u>

  • f(x) = x₁³ = x₂³ ⇒ x₁ = x₂, both are natural numbers

It it confirmed one-to-one, hence it is injective

<u>Check the surjectivity:</u>

f(x) = y ∈ N

  • x³ = y
  • y = ∛x

<u>Let y = 2, then:</u>

  • 2 = x³
  • x = ∛2 ∉ N

Since x is not natural, the function is not surjective

6 0
2 years ago
Read 2 more answers
Which expression has a solution of 6, if r=4
Pani-rosa [81]

r+2

Explanation:

because if we add 2 to r which is equal to 4 we can get 6

5 0
3 years ago
Read 2 more answers
Calculate the surface area of the aquarium, without the top.<br>24 cm<br>80 cm<br>16 cm​
larisa86 [58]
Well you never sent a picture but the most logical answer is 80 cm
3 0
2 years ago
Write a polynomial function of minimum degree with real coefficients whose zeros include those listed. Write the polynomial in s
wolverine [178]

Answer:

x^4 - 14x^2 - 40x - 75.

Step-by-step explanation:

As complex roots exist in conjugate pairs the other zero is -1 - 2i.

So in factor form we have the polynomial function:

(x - 5)(x + 3)(x - (-1 + 2i))(x - (-1 - 2i)

= (x - 5)(x + 3)( x + 1 - 2i)(x +1 + 2i)

The first 2 factors  = x^2 - 2x - 15 and

( x + 1 - 2i)(x +1 + 2i) = x^2 + x + 2ix + x + 1 + 2i - 2ix - 2i - 4 i^2

=  x^2 + 2x + 1 + 4

= x^2 + 2x + 5.

So in standard form we have:

(x^2 - 2x - 15 )(x^2 + 2x + 5)

= x^4  + 2x^3 + 5x^2 - 2x^3 - 4x^2 - 10x - 15x^2 - 30x - 75

= x^4 - 14x^2 - 40x - 75.

7 0
3 years ago
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