All categories

3 years ago

2(rt-4+2) when r=5 and t=2

Mathematics

1 answer:

Whitepunk [10]3 years ago

8 0

Answer:

Step-by-step explanation:

2(5x2-4+2)=2(10-4+2)=2x4=8

You might be interested in

A store is advertising a 40% off sale. Find the new price of a pair of boots that were originally marked $149.00.

Alinara [238K]

Answer:

Step-by-step explanation:

Okay well if 149=100% and there is a 40% we just have to find 60% and to do that we just multiply 149 by 0.60 to get 89.4

149*0.60=89.6

5 0

3 years ago

Write (3 − 7i) − (-11 + 5i) as a complex number in standard form.

Katyanochek1 [597]

I believe its 10-6i im pretty sure

7 0

4 years ago

Read 2 more answers

Can anyone explain to me how to do this question ? ty !!

julia-pushkina [17]

Step-by-step explanation:

use a little imagination.

the whole thing is a combination of churches and half- circles.

and you know the formula for the area of a circle ?

A = pi×r²

so, the only difficulty is to find the circles and then the radius of each involved circle.

when you look at the picture, the shaded area is almost identical to the lower half of the main circle.

2 bumps "look" over into the other side, but one equally sized bump is removed from this lower half.

so, as a first step we will calculate the area of the lower half of the main circle.

the diameter is 24 m, so the radius is half of that : 12m

the area of the large circle is therefore

pi×12² = 144×pi m²

since we only need the (lower) half, we divide this by 2 :

144×pi / 2 = 72×pi m²

the bumps up and down are actually half-circles too. just of smaller circles.

since AB = BC = CD, we know each of these lines are 1/3 of the main diameter AD.

so, the diameter of the smaller circles is 24/3 = 8 m

and their radius is half of that = 8/2 = 4m

the area of such a small circle is therefore

As = pi×4² = 16×pi m²

and a small half-circle area is then

16×pi / 2 = 8×pi m²

so, for the full shaded area I need to take the large half-circle and add 2 small half-circles, and then subtract 1 small half-circle.

so, in total I only need to add 1 small half-circle.

Ashaded = 72×pi + 8×pi = 80×pi m²

5 0

3 years ago

How many child tickets were sold that day?

ExtremeBDS [4]

$\huge\boxed{\fcolorbox{black}{red}{Answer}}$

first let's name a couples of variable

• the number of adults tickets sold: a

• the number of children tickets sold: c

From the problem we know

a + c = 128

and

$5.40c + $9.20a = $976.20

1) solve the equation to alpha

a+c-c = 128 -c

a+0=128-c

a=128-c

2) substitute (128 - c) for a in the second equation and solve to c

$5.40c + $9.20a = $976.20 become

$5.40c + $9.20(128 - c) = $976.20

$5.40c + ($9.20 × 128) - ($9.20 - c) = $976.20

$5.40c - $9.20c + $ 1177.6 = $976.20

($5.40 - $9.20)c +$1177.6 = $976.20

-$3.80c + $1177.6 = $9.76.20

-$3.80c + $1177.60 - $1177.60 = $976.20 - $1177.60

-$8.30c + 0 = $201.40

-$3.80c = - $201.40

-$3.80c. -$201.40

________. = _________

-$3.80. -$3.80

-$3.80c. -$201.40

________. = _________. - they are 4 cut the no

-$3.80. -$3.80

c = $201.40

________

3.80

c = 53

3 0

2 years ago

Jed entered the following values into the TVM Solver on his graphing calculator.

Elden [556K]

Answer: 17.7

Step-by-step explanation:

69/ 3.9%•100= 17.69= 17.7

8 0

3 years ago

Read 2 more answers