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IgorC [24]
3 years ago
12

The derivative of y=2x^2+x+2​

Mathematics
1 answer:
Lorico [155]3 years ago
5 0

Answer:

4x + 1

Step-by-step explanation:

y = 2x² + x + 2

dy/dx = 2(2x¹) + 1 + 0

dy/dx = 4x + 1

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Work out the area of a parallelogram of base 5m and height 3m
Arada [10]
B*H= area so 3*5= 15

15 is your answer
6 0
3 years ago
-2(7-15)<br>What is the value of<br>4<br>?<br>-4<br>-2<br>02.<br>O 4​
galben [10]

Answer:

16

Step-by-step explanation:

=-2(7-15)

USING 'BODMAS' RULE

= -2(-8)

= -2*-8

= 16

7 0
2 years ago
23 + 8m + 4n - 5m - 27​
mylen [45]

Answer:

-4 + 3m + 4n

Step-by-step explanation:

In this question, you are combining like terms, meaning doing equations to numbers that fit with only each other.

<u>So we should start on the number without variables:</u>

23 and 27

<u>Match them up together and you should find your first equation:</u>

23 - 7

==> -4

So we should have  -4  +  8m  +  4n  -  5m

Now we should combine the numbers with the variable of m:

8m and 5m

<u>Match them up together and you should find your first equation:</u>

<u></u>

8m - 5m

==> 3m

So we should now have -4  + 3m  + 4n

<u></u>

<u>Since there are no other variables of n, we are all done:</u>

<u>-4  + 3m  + 4n  is  your  final  answer </u>

4 0
3 years ago
Give 1 pair of Vertical and 1 pair of Supplementary angles
mojhsa [17]

Solution:

Vertical angles are a pair of opposite angles formed by intersecting lines. re vertical angles. Vertical angles are always congruent.

These two angles (140° and 40°) are Supplementary Angles because they add up to 180°:

Notice that together they make a straight angle.

Hence,

From the image

The following pairs form vertical angles

\begin{gathered} \angle1=\angle3(vertical\text{ angles)} \\ \angle2=\angle4(vertical\text{ angles)} \\ \angle5=\angle7(vertical\text{ angles)} \\ \angle6=\angle6(vertical\text{ angles)} \end{gathered}

Hence,

One pair of the vertical angles is ∠1 and ∠3

Part B:

Two angles are said to be supplementary when they ad together to give 180°

Hence,

From the image,

The following pairs are supplementary angles

\begin{gathered} \angle5+\angle6=180^0(supplementary\text{ angles)} \\ \angle5+\angle8=180^0(supplementary\text{ angles)} \\ \angle7+\angle8=180^0(supplementary\text{ angles)} \\ \angle6+\angle7=180^0(supplementary\text{ angles)} \\ \angle1+\angle2=180^0(supplementary\text{ angles)} \\ \angle1+\angle4=180^0(supplementary\text{ angles)} \\ \angle2+\angle3=180^0(supplementary\text{ angles)} \\ \angle3+\angle4=180^0(supplementary\text{ angles)} \end{gathered}

Hence,

One pair of supplementary angles is ∠5 and ∠6

8 0
1 year ago
A local farm sells strawberries and blueberries. The ratio of the number of strawberries to blueberries it sells at 5:3. If it s
olganol [36]

Answer:

125

Step-by-step explanation:

The ratio is 5:3 so we divide the 75 by 3 to get 1 part

1 part = 75

75 x 5 = 125

125 strawberries were sold :)

3 0
2 years ago
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