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kykrilka [37]
3 years ago
10

Sam spun a spinner that is evenly spaced and numbered from 1 to 10. When it stopped, Sam spun it again. What is the probability

that the spinner stopped on a number less than 4 on the first spin and on an odd number on the second spin?
a 1/5
b 1/10
c 3/20
d 2/25
Mathematics
2 answers:
Oliga [24]3 years ago
6 0

2/10=1/5

your answer is A

earnstyle [38]3 years ago
6 0

Answer:

<h2>C. 3/20</h2>

Step-by-step explanation:

First, we need to find the probability of a number less than 4. Notice that there are only three possible events, number 1, number 2 and number 3.

So, the probability of a number less than 4 is

P_{

On the other hand, there are 5 odd number, which are 1, 3, 5, 7 and 9. So, the probability of getting an odd number is

P_{odd}=\frac{5}{10}=\frac{1}{2} =0.50 (or \ 50\%)

Therefore, the probaility of getting these outcomes in two spins is

P=\frac{3}{10} \times \frac{1}{2}=\frac{3}{20}

So, the right answer is C.

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Popular Problems Algebra Solve for x 64^(4x)=16^(x+1)

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2

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