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2 years ago

Use the Unit Circle to find the exact value of the inverse trig function.

Mathematics

1 answer:

Vedmedyk [2.9K]2 years ago

5 0

Answer:

330

Step-by-step explanation:

When we are at 30 degrees on the unit circle, we are at the point ( $\sqrt3$ /2, 1/2) so if we go to -30 degrees (330 degrees), we will be at point (- $\sqrt3$ /2, -1/2).

Note: (cosine, sine)

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Does a graph compare two variables or not

Grace [21]

Answer:

I believe it depends on the equations..

Step-by-step explanation:

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3 years ago

Find all the zeros of the polynomial function p(x) = x3 – 5x2 + 33x – 29

hram777 [196]

Answer:

$\large \boxed{\sf \ \ x=1, \ \ x=2+5i, \ \ x=2-5i \ \ }$

Step-by-step explanation:

Hello,

I assume that we are working in $\mathbb{C}$ , otherwise there is only one zero which is 1. Please consider the following.

First of all, <u>we can notice that 1 is a trivial solution</u> as

$p(1) = 1^3-5\cdot 1^2 + 33\cdot 1-29=1-5+33-29=0$

It means that (x-1) is a factor of p(x) so we can find two real numbers, a and b, so that we can write the following.

$p(x)=(x-1)(x^2+ax+b)=x^3+ax^2+bx-x^2-ax-b=x^3+(a-1)x^2+(b-a)x-b$

Let's identify like terms as below.

a-1 = -5 <=> a = -5 + 1 = -4

b-a = 33

-b = -29 <=> b = 29

$\boxed{ \ p(x)=(x-1)(x^2-4x+29) \ }$

Now, we need to find the zeroes of the second factor, meaning finding x so that:

$x^2-4x+29=0 \ \text{ complete the square, 29 = 25 + 4} \\ \\ x^2-2\cdot 2 \cdot x+2^2+25=0 \\ \\ (x-2)^2=-25=(5i)^2 \ \text{ take the root } \\ \\x-2=\pm 5i \ \text{ add 2 } \\ \\ x = 2+5i \ \text{ or } \ x = 2-5i$

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

5 0

3 years ago

<img src="https://tex.z-dn.net/?f=A%28x%29%3D3%5E2" id="TexFormula1" title="A(x)=3^2" alt="A(x)=3^2" align="absmiddle" class="la

kogti [31]

It is good equation. Look, that:
81 = 3 x 3 x 3 x 3 = 3^4.
So you have to solve:
3^x = 3^4
exponents have to be the same, so
x=4
That's mean that A(4) = 81

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3 years ago

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Murljashka [212]

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3 years ago

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3 years ago

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