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4 years ago

Can someone help please?

Mathematics

2 answers:

monitta4 years ago

7 0

Answer:

Step-by-step explanation:

y-4x=1

it crosses y-axis where x=0

y-4(0)=1

y=1

so point is (1,0)

y=2x+c

∵(0,-3) lies on it.

-3=2(0)+c

c=-3

so y=2x-3

∵(k,10) lies on it.

10=2k-3

2k=13

k=13/2

balandron [24]4 years ago

6 0

Answer:

One sec

Step-by-step explanation:

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MY HEAD IS HURTING I BEG FOR YOUR HELP. I WILL MARK BRAINLIST!!

andreev551 [17]

Answer: No association

Step-by-step explanation:

There is absolutely no pattern going on. This means that the miles ran per week are not really affecting the standing heartbeat. Therefore, I'd say there is no association.

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3 years ago

The difference of Vidya’s height and 15 is 74?

Luba_88 [7]

Answer: V - 15 = 74; V = 89

Step-by-step explanation:

"difference" means subtraction

"is" means equals

Vidya's height minus 15 is 74

V - 15 = 74

To solve, add 15 to both sides: V - 15 + 15 = 74 + 15

V = 89

4 0

3 years ago

Because of an accident Royce was involved in, his insurance company has increased his annual premium for auto insurance

Vesna [10]

Answer:

New Premium = $571.24

Step-by-step explanation:

Current premium = $22.50 + $144.75 + $275.75 + $100.00 = $543.00

New Premium = Current Premium x (1 + 0.052)

New Premium = $543.00 x 1.052

New Premium = $571.24

8 0

4 years ago

A 12 feet tall street light is making an 18 feet shadow at the same time in nearby building is making a 72 feet shadow

Harman [31]

Answer: 48 ft

Step-by-step explanation:

Given

Height of street light h=12 ft

length of shadow x=18 ft

Shadow length of building x'=72 ft

suppose the height of the building is y

from the figure, we can write

$\Rightarrow \tan p=\dfrac{h}{x}=\dfrac{12}{18}\\\\\Rightarrow \tan p=\dfrac{y}{x'}=\dfrac{12}{18}\\\\\Rightarrow y=72\times \dfrac{2}{3}=48\ ft$

7 0

3 years ago

in the figure below trianglePQM and triangleQRP are right triangles. the measure of lineQM is 6 and the measure of lineQP is 8.

Kipish [7]

Answer:

Option 4 is correct. The length of PR is 6.4 units.

Step-by-step explanation:

From the given figure it is noticed that the triangle PQR and triangle MQR.

Let the length of PR be x.

Pythagoras formula

$hypotenuse^2=base^2+perpendicular^2$

Use pythagoras formula for triangle PQM.

$PM^2=QM^2+PQ^2$

$PM^2=(6)^2+(8)^2$

$PM^2=36+64$

$PM^2=100$

$PM=10$

The value of PM is 10. The length of PR is x, so the length of MR is (10-x).

Use pythagoras formula for triangle PQR.

$PQ^2=QR^2+PR^2$

$(8)^2=QR^2+x^2$

$64-x^2=QR^2$ .....(1)

Use pythagoras formula for triangle MQR.

$MQ^2=QR^2+MR^2$

$(6)^2=QR^2+(10-x)^2$

$36=QR^2+x^2-20x+100$

$36-x^2+20x-100=QR^2$ .... (2)

From equation (1) and (2) we get

$36-x^2+20x-100=64-x^2$

$20x-64=64$

$20x=128$

$x=6.4$

Therefore length of PR is 6.4 units and option 4 is correct.

3 0

3 years ago