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Dmitriy789 [7]
3 years ago
5

Emigration. In 2007, 51% of all emigrants to Canada were males, 82% were at least 18 years old, and 42% were male of at least 18

years of age. Find the probability that a randomly selected person who emigrated Canada in 2007 was:
a) Male and under 18 years old.
b) Either male or at least 18 years of age.
c) Female and under 18 years old.

Mathematics
1 answer:
LenaWriter [7]3 years ago
5 0
<h3>Answer:</h3>
  • a) 9%
  • b) 91%
  • c) 9%
<h3>Explanation:</h3>

It can help to make a table from the given information. The attached table is filled in from the given values (underlined in green). We know that rows and columns must add to 100%, so the remaining numbers are easily found by subtraction.

a) This is the number in the upper left corner, 9%.

b) This is the sum of the over 18 row (82%) and the number in (a), so is ...

... 82% +9% = 91%.

Alternatively, it is the sum of the male column (51%) and the over 18 female number (40%):

... 51% +40% = 91%.

It is also the complement of the number in (c).

c) This is the number in the upper center box, 9%.

It is also the complement of the number in (b).

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According to the Bureau of Labor Statistics, citizens remain unemployed for an average of 15.9 weeks before finding their next j
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Complete Question

According to the Bureau of Labor Statistics, citizens remain unemployed for an average of 15.9 weeks before finding their next job (June, 2008). Suppose you want to show that Louisiana has been effective in getting their unemployed back to work sooner. You take a random sample of 50 citizens who were unemployed six months earlier and ask them to report the duration. You find that the average time spent unemployed was 13.4 weeks with a sample standard deviation of the time unemployed is 6.7 weeks.

1 Which of the following statements is the correct alternative hypothesis?

2 The test statistic for testing the hypothesis is

a. -2.64

b. -2.32

c. -2.11

d. -1.28

e. none of these are correct

Answer:

1  

 The  alternative hypothesis  H_a  :  \mu < 15.9

2

The  test statistics z =  -2.64  

Step-by-step explanation:

From the question we are told that

     The population  mean value for time  citizens remain unemployed is  \mu  =  15.9 \  weeks

     The  sample size is  n =  50

     The  sample standard deviation is  6.7 weeks.

      The  sample mean value for time  citizens remain unemployed is  \mu  =  15.9 \  weeks

       

     The  null hypothesis is  H_o  :  \mu \ge 15.9

      The  alternative hypothesis  H_a  :  \mu < 15.9

Generally test statistics is mathematically represented as

       z =  \frac{ \= x  - \mu }{ \frac{s}{\sqrt{n} } }  

=>    z =  \frac{13.4 - 15.9}{\frac{6.7}{\sqrt{50}}}

=>     z =  -2.64  

   

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