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never [62]
3 years ago
6

If a can of soup is $2.00 how many cans can you buy with $17?( Remember you can not buy a part of a can so round down)

Mathematics
1 answer:
dimaraw [331]3 years ago
6 0

Answer:

8 cans

count by 2's until you get to 8. It's simple.

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If a+b+c=0 for a,b,c then prove a²/bc+b²/ca+c²/ab=3.
Ierofanga [76]
According to the identity if a+b+c=0
then a3+b3+c3=3abc
a3+b3+c3/abc=3
a2*a/bc*a+b2*b/ca*b+c2*c/ab*c=3
cancel a,b,c in   all the fraction then you get
<span>a²/bc+b²/ca+c²/ab=3. 
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5 0
3 years ago
Jade had $100 yesterday. Today she earns d dollars for babysitting. She now has $148. Write an equation to match how much money
ELEN [110]
100 + 48=148  so that means she got 48 dollars for babysitting 
8 0
3 years ago
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What are 5 numbers that have 3 ,5 and 7 as prime factors
Leya [2.2K]
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4 0
3 years ago
The seventh term of an arithmetic progression is equal to twice the fifth term. The sum
mario62 [17]

Answer:

a₁ = - 24

Step-by-step explanation:

The n th term of an AP is

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Given a₇ = 2a₅ , then

a₁ + 6d = 2(a₁ + 4d) = 2a₁ + 8d ( subtract 2a₁ + 8d from both sides )

- a₁ - 2d = 0 → (1)

The sum to n terms of an AP is

S_{n} = \frac{n}{2} [ 2a₁ + (n - 1)d ]

Given S_{7} = 84 , then

\frac{7}{2} (2a₁ + 6d) = 84

3.5(2a₁ + 6d) = 84 ( divide both sides by 3.5 )

2a₁ + 6d = 24 → (2)

Thus we have 2 equations

- a₁ - 2d = 0 → (1)

2a₁ + 6d = 24 → (2)

Multiplying (1) by 3 and adding to (2) will eliminate d

- 3a₁ - 6d = 0 → (3)

Add (2) and (3) term by term to eliminate d

- a₁ = 24 ( multiply both sides by - 1 )

a₁ = - 24

6 0
3 years ago
Whats the answer i have no idea
VMariaS [17]

Answer:

1 over 8

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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