According to the identity if a+b+c=0
then a3+b3+c3=3abc
a3+b3+c3/abc=3
a2*a/bc*a+b2*b/ca*b+c2*c/ab*c=3
cancel a,b,c in   all the fraction then you get
<span>a²/bc+b²/ca+c²/ab=3. 
</span>hence proved
        
             
        
        
        
100 + 48=148  so that means she got 48 dollars for babysitting 
        
                    
             
        
        
        
The 5 number that have 3 ,5 and 7 as prime number are 23, 31, 37, 43, 53. and if you want there 57,47, 103.
        
             
        
        
        
Answer:
a₁ = - 24
Step-by-step explanation:
The n th term of an AP is
 = a₁ + (n - 1)d
 = a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Given a₇ = 2a₅ , then
a₁ + 6d = 2(a₁ + 4d) = 2a₁ + 8d ( subtract 2a₁ + 8d from both sides )
- a₁ - 2d = 0 → (1)
The sum to n terms of an AP is
 =
 =  [ 2a₁ + (n - 1)d ]
 [ 2a₁ + (n - 1)d ]
Given  = 84 , then
 = 84 , then
 (2a₁ + 6d) = 84
 (2a₁ + 6d) = 84 
3.5(2a₁ + 6d) = 84 ( divide both sides by 3.5 )
2a₁ + 6d = 24 → (2)
Thus we have 2 equations
- a₁ - 2d = 0 → (1)
2a₁ + 6d = 24 → (2)
Multiplying (1) by 3 and adding to (2) will eliminate d
- 3a₁ - 6d = 0 → (3)
Add (2) and (3) term by term to eliminate d
- a₁ = 24 ( multiply both sides by - 1 )
a₁ = - 24
 
        
             
        
        
        
Answer:
1 over 8
Step-by-step explanation: